Question

pplication)Using multiple models simultaneously: This FNT refers to a processinvolving three moles of a diatomic gas (which behaves as an ideal gas).The PV curve at right describes this process.Assume, as is typical near room temperature,vibrational modes are frozen out.a)Determine the energy transferred as work, the change in internal energy, and the energy transferred as heat in this process. b)Could youhave stillansweredthe questions in a) if the temperature was not provided on the plot

Answer 1

Complete Question

Questions Diagram is attached below

Answer:

*  $W=1142.86Joule$

*  $Q=997.7J$

*  $H=2140.5J$

Explanation:

From the question we are told that:

Temperature $T=337K$

Pressure $P=(60-55)Pa*10^5$

Volume$V=(1.6-1.4)m^3*10^{-3}$

Generally the equation for gas Constant is mathematically given by

$\frac{P_2}{P_1}=\frac{V_1}{V_2}^n$

 $\frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n$

 $n=0.65$

Therefore

Work-done

 $W=\int{pdv}$

 $W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}$

 $W=1142.86Joule$

Generally the equation for internal energy is mathematically given by

 $Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}$

 $Q=997.7J$

Therefore

 $H=Q+W$

 $H=997.7J-11.42.9$

 $H=2140.5J$