Hello, Lindaparker, a spit could form from a rocky headland where prevailing winds would
blow at an angle to the rocky headland, gradually depositing sand and
shingle at that place. A spit is a permanent land form resulting
from marine deposition and wind deposition. It is usually a long and
narrow accumulation of sand or shingle with one joined to the land and
the other end projecting at a narrow angle out into the sea. Salt marshes sometimes form on the sheltered side of a spit.
Answer:
2.05 x 10²⁴ molecules
Explanation:
The balanced equation for the chemical reaction is the following:
2 HCl + Mg → MgCl₂ + H₂
According to the equation, 2 moles of HCl are required to react with 1 mol of magnesium (Mg), so the moles of HCl required to react with 1.7 mol Mg are calculated as follows:
moles HCl = 1.7 mol Mg x 2 mol HCl/mol Mg = 3.4 mol HCl
We know that 1 mol of any compound is equal to 6.022 x 10²³ molecular entities, so we convert the moles of HCl to molecules as follows:
molecules HCl = 3.4 mol HCl x 6.022 x 10²³ molecules/1 mol = 2.05 x 10²⁴ molecules
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Explanation:
The only flaw I can find is you squared 3 instead of cubing it and it will be 27X^4 instead of 9x^4.
This reduces the amount slightly, but the number is still incredibly high (about 10 ^ 5 L is what I've calculated). Your professor might want to point out that this will not be a effective experiment due to the large volume of saturated
The Ksp value of Ca(OH)2 on the site (I used 5.5E-6 [a far more soluble compound than Al(OH)3]) and estimated how much of it will be needed. My calculation was approximately 30 ml. If you were using that much in the experiment, it implies so our estimates for Al(OH)3 are right, that the high amount is unreasonably big and that Al(OH)3 will not be a suitable replacement unless the procedure was modified slightly.
Answer:
12.5
Explanation:
After three half-lives, one eighth (1/2 x 1/2 x 1/2) of the uranium-238 will remain. One-eighth equals 12.5%