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Vinil7 [7]
2 years ago
10

3k+aici3 3kci+ai is what type of reaction

Chemistry
1 answer:
exis [7]2 years ago
3 0
3K      +     AlCl3 -------->  3 KCl     +          Al
element    compound     compound       element

This is single replacement (displacement) reaction.
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What is a possible cause of a large percentage of error in an experiment where mgo is produced from the combustion of magnesium?
PilotLPTM [1.2K]

A possible cause of a large percentage of error in an experiment where MgO is produced from the combustion of magnesium would be not all of the Mg has completely reacted. <span>

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4 0
2 years ago
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The energy that a log has is transformed when burned. How does the chemical energy of the log compare to the heat and light ener
SCORPION-xisa [38]
The amount of chemical energy is equal to the amount of heat and light energy.

This is due to the principle of conservation of energy, which states that the total energy of a system remains constant. 
4 0
3 years ago
How many grams are there in 7.5x10^23 molecules of H2SO4
horsena [70]
Moles of H2SO4= 7.5x10^23/ 6.02x10^23 = 1.25 (3sf) moles of H2SO4

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6 0
2 years ago
A gas mixture with 4 mol of Ar, x moles of Ne, and y moles
maks197457 [2]

Answer:

a) \Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]

b) x=4

c) \Delta G_{max}=-2721.9 J/mol

Explanation:

Gas mixture:

n_{Ar}= 4 mol

n_{Ne}= x mol

n_{Xe}= y mol

n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}

n_{Ne} + n_{Xe}=2*n_{Ar}

x + y=8 mol

y=8 mol- x

Mol fractions:

x_{Ar}=\frac{4 mol}{12 mol}=1/3

x_{Ne}=\frac{x mol}{12 mol}=x/12

x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12

Expression of \Delta G_{mixing}

\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)

\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]

\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]

Expression of \Delta G_{max}

\frac{d \Delta G_{mixing}}{dx}=0

\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]

0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)

0=[ln (x/12)-ln ((8-x)/12)

ln (x/12)=ln ((8-x)/12)

x=(8-x)

x=4

\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]

\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]

\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]

\Delta G_{max}=-2721.9 J/mol

4 0
3 years ago
Answer this question pleas
Korvikt [17]

Answer:nope

Explanation:

Just no

4 0
2 years ago
Read 2 more answers
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