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inysia [295]
3 years ago
5

how many liters of nitrogen gas are needed to react with 90.0 g of potassium at STP in order to produce potassium nitride accord

ing to the following reactions?
Chemistry
2 answers:
Snezhnost [94]3 years ago
7 0
The atomic mass of potassium is 19 g/mol
90.0 g of potassium contains ;
   = 90.0/19 
   = 4.737 moles
The reaction between potassium and nitrogen is given by the equation;
 6K + N2 = 2K3N
The mole ratio of potassium and nitrogen is 6:1
The number of moles of nitrogen;
    = 4.737/6
    = 0.7895 moles
But, 1 mole of nitrogen occupies 22.4 liters at STP
Therefore; 0.7895 moles × 22.4 liters
                 = 17.685 liters

MaRussiya [10]3 years ago
7 0

Answer:8.59L

Explanation:

The other answer has all the right steps but the atomic mass of potassium is actually 39.098 not 19.

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Answer: 15062.4 Joules

Explanation:

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Since,

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Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2

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