1. circle graph
2. Bar graph
3. line graph
hope this helps
Answer : The heat change of the cold water in Joules is, 
Explanation :
First we have to calculate the mass of cold water.
As we know that the density of water is 1 g/mL. The volume of cold water is 45 mL.


Now we have to calculate the heat change of cold water.
Formula used :

where,
Q = heat change of cold water = ?
m = mass of cold water = 45 g
c = specific heat of water = 
= initial temperature of cold water = 
= final temperature = 
Now put all the given value in the above formula, we get:


Therefore, the heat change of cold water is 
Answer:
1) the capacitance of the capacitor increases. This is due to the induction of opposite charges on the two surfaces of the dielectric by the plate, this increased the charge in the field, from C =Q/v, it is seen that capacitance C will increase with increase in Q since v is constant.
2) the electric field intensity will also increase with increase in electric charges provided plate separation d remains constant.
It is actually are tools that make work easier C because i just had it on study island
Answer:
0.44807175m
Explanation:
k = Spring constant =
(Assumed, as it is not given)
g = Acceleration due to gravity = 9.81 m/s²
Total mass is

The total weight will balance the spring force

The springs are compressed by 0.44807175m