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slavikrds [6]
3 years ago
5

A(n) ____________ image cannot be projected and forms where light rays appear to originate.

Physics
2 answers:
IrinaVladis [17]3 years ago
6 0
A virtual image is the answer.
Sedbober [7]3 years ago
6 0
<h3><u>Answer;</u></h3>

Virtual image

A<em><u> virtual image</u></em> cannot be projected and forms where light rays appear to originate.

<h3><u>Explanation</u>;</h3>
  • <em><u>A virtual image is an image that can not be formed on a screen. This type of an image is formed when the rays of light appear to meet at a point after reflection or refraction. Virtual images are always erect or upright.</u></em>
  • <em><u>A real image on the other hand, is an image that can be formed on a screen. Real image is formed when the rays of light meet at some point after reflection or refraction. Real images are always inverted.</u></em>
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What is the dimensional formula of thermal conductivity?​
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Answer:

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A student allows the evaporating dish and the anhydrous salt for a long time on the lab bench. What will happen to the mass of t
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4 0
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Do this work if someone give correct answer I make her brainliest do this worksheet please
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Sry,I only know the answer of q2

Chlorine is a non metal because it is bad conductor of heat and sodium is a metal because it is good conductor of heat.

The 3 ways in which metal is different from non metal are given below:

1)metal are good conductor of heat but nonmetal are bad conductor of heat.

2)metals are malleable but non metal aren't malleable.

3)metals are generally ductile but non metal aren't ductile.

Hope it will helpyou!

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Two objects (38.0 and 17.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
fgiga [73]

Answer:

a) 3.7 m/s^2

b) 231.8 N

Explanation:

Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2

a)

F1 = m1g and F2 = m2g

So Fnet = F1 + F2

Since the pulleys will move in different directions when accelerating...

Fnet = F1 - F2

M×a = m1g - mg2

M×a = g×(m1 -m2)

a = g×(m1 - m2)/M

a = 9.8×(38 - 17)/(38 + 17)

a = 3.7 m/s^2

b)

Looking at the part for m2

Fnet  = T - m2g

-m2×a = T - m2g

T = m2(g - a)

T = 231.8 N

7 0
3 years ago
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