Hey there! I believe this statement is False. No two fragments are exactly the same size, and all fragments vary on the density of the material, the speed at which it broke off of the material, and the amount of it that hit the ground. Because of this, some people may say "Oh, this is the same size as this," but in reality, nothing is exactly the same size. At least, on a molecular level. So the statement above is false.
Hope this helped!
Thanks!
~Steve
Answer: NOT accurate, but precise.
[translation: You screwed up, but did it in style].
Explanation:
The average mass measurement is 41.95g. Compared to the actual value of 28.0 grams, the measurement is NOT accurate.
The standard deviation for the data is 0.112. Dependiong on your definition of precision, this looks relatively good. I would go for precise.
The heat that cooks it, is matter as well..
Hope this helps :)
Explanation:
To determine the charge on a given transition metal atom, you have to consider what element it is, the charges on the other atoms in the molecule, and the net charge on the molecule itself. The charges are always whole numbers, and the sum of all the atomic charges equals the charge on the molecule
Answer:
the water concentration at equilibrium is
⇒ [ H2O(g) ] = 0.0510 mol/L
Explanation:
- CH4(g) + H2O(g) ↔ CO(g) + 3H2(g)
∴ Kc = ( [ CO(g) ] * [ H2 ]³ ) / ( [ CH4(g) ] * [ H2O(g) ] ) = 0,30
⇒ [ CO(g) ] = 0.206 mol / 0.778 L = 0.2648 mol/L
⇒ [ H2(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L
⇒ [ CH4(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L
replacing in Kc:
⇒ ((0.2648) * (0.2404)³) / ([ H2O(g) ] * 0.2404 ) = 0.30
⇒ 0.0721 [ H2O(g) ] = 3.679 E-3
⇒ [ H2O(g) ] = 0.0510 mol/L
