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masya89 [10]
3 years ago
14

How to get infinite thanks could you show me please ☺️​

Physics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer: divide by zero, or square root of a negative

Explanation: If your question is how to get infinity as an answer to a problem, that generally means that the answer is undefined or doesn't exist.

A couple of ways to get that...

  1. You try to divide by zero. In other words, a problem that asks you to perform something like this:  5/0=   or 23/(4-4)=   Such a problem will give you an error on a calculator because the answer is infinity or doesn't exist.
  2. Another way is to try to get the square root of a negative number. That answer doesn't exist as a real number, so \sqrt{-4\\} will also give you an error on a calculator.

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How does the electric forest between charged objects change as objects move away from each other
ra1l [238]
The law looks at the forces created between two charged objects. As distance increases, the forces and electric fields decrease. Positive and negative charges like to move towards each other. Similar charges such as two positive or two negative push away from each other.
4 0
4 years ago
What is the mass of a neutron?
astraxan [27]
_______________________//__/1 amu
3 0
3 years ago
Read 2 more answers
An amusement park designer wants his swing to have a centripetal acceleration of 24 m/s2. If the velocity of the swing is 11 m/s
viva [34]

Answer:

<u>radius</u><u> </u><u>is</u><u> </u><u>C</u><u>:</u><u> </u><u>5</u><u>.</u><u>0</u><u> </u><u>m</u>

Explanation:

formular for centripetal acceleration:

a =  \frac{ {V}^{2} }{r}

a is acceleration

V is velocity

r is radius

24 =  \frac{ {11}^{2} }{r}  \\  \\ r =  \frac{ {11}^{2} }{24}  \\  \\ r = 5.0 \: m

5 0
3 years ago
Read 2 more answers
In a Young’s interference experiment, the two slits are separated by 0.150 mm and the incident light includes two wavelengths: l
dezoksy [38]

Answer:

2.52 × 10⁻² cm

Explanation:

The distance of bright fringe from the center of the screen is given by the formula

                y = \frac{m\lambda D}{d}

Here, wavelength is λ, Distance of the screen from the slits is D, seperation between the

slits is d.

   

Separation between the slits, d = 0.15 mm

                                                     = 0.15 * 10^{-3} m

Distance of the screen from the slits = 1.40 m

We have a wavelength, λ1 = 540 nm

                                           = 540 * 10^{-9} m

By substituting all these values in the above equation we get

                y1 = mλD/d

                y1 = m(540 \times 10^{-9} m)(1.40 m)/(0.15 \times 10^{-3} m)

                y1 = m(5.04 * 10^{-3} m)

We have a wavelength, λ2 = 450 nm

                                           = 450 * 10^-9 m

By substituting all these values in the above equation we get

                y_2 = \frac{m\lambda D}{d}

                y_2 = m(450 * 10^{-9} m)(1.40 m)/(0.15 * 10^{-3} m)

                y_2 = m'(4.20 * 10^{-3} m)

According to the problem, these two distance are coincides with each other.

So,

                           y_1 = y_2

m(5.04 * 10^{-3} m) = m'(4.20 * 10^{-3} m)

by testing values, the above equation is satisfied only when, m = 5 and m' = 6

Then from the above we have

                           y1 = y2 = 0.0252 m

                                         = 2.52 × 10⁻² cm

8 0
3 years ago
A block of mass m = 2.0 kg lies on a rough ramp that is inclined at an angle θ = 20oto the horizontal. A force F of magnitude 5.
Marina86 [1]

Answer:

a) 0.64 b) 2.17m/s^2 c) 8.668joules

Explanation:

The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,

Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move

Frictional force = mgsin20o + 5N = 6.71+5N = 11.71

The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44

Coefficient of static friction = 11.71/18.44= 0.64

Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)

b) coefficient of kinetic friction = frictional force/ normal force

Fr = 0.4* mgcos 20o = 7.375N

F due to motion = ma = total force - frictional force

Ma = 11.71 - 7.375 = 4.335

a= 4.335/2(mass of the block) = 2.17m/s^2

C) work done = net force *distance = 4.335*2= 8.67Joules

8 0
3 years ago
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