Answer:
Oxidation half
Ca -----> Ca2+ +2elecyrons
Reduction half
Cl2 + 2electrons ------> 2Cl-
Explanation:
Answer:
2.85moles of oxygen gas
Explanation:
Given parameters:
Volume of oxygen gas = 63.8L
Unknown:
Number of moles = ?
Solution:
We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:
1 mole of a gas at STP occupies a volume of 22.4L
So;
63.8L of oxygen gas will take up a volume of
= 2.85moles of oxygen gas
The boiling point increase of a solution is a colligative property, which means that it is related with the solvent and the concentration of the solute, as per this formula:
ΔT = i * kb * m
Where, ΔT is the increase in the boiling point, i is the van't Hoof factor (which accounts for the numberof particles that are dissolved), kb is the boiling point and m the molality of the solution.
Gvien the normal boiling point of 100°C for pure water, ΔT = 101.4 °C - 100.0 °C = 1.4 °C.
Kb = 0.512 °C / m
m = 1.2 m
Therefore, i = ΔT / (kb * m) = 1.4°C / (0.512 °C/m * 1.2m) = 2.28
Answer: 2.28
lol im a senior in high school (12th grade) and I dont even know this stuff or i forgot it either way im pretty sure im just dumb
