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2 years ago

Which of the following is an example of acceleration?

Chemistry

2 answers:

anzhelika [568]2 years ago

4 0

Answer:

it's either B. or C.. hope this helps!

Explanation:

garik1379 [7]2 years ago

4 0

Answer:

D. A bus moves on a straight road and then makes a right turn.

Explanation:

Acceleration is a change in direction or speed. All of the other examples involve straight lines or constant speed.

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What is the difference between theme and plot?

VladimirAG [237]

Answer:

should be D

Explanation:

3 0

2 years ago

Read 2 more answers

What does the cell theory state?

strojnjashka [21]

C, that cells cannot be created nor destroyed.

Cells are produce by other cells. Cells can not be man-made nor destroyed.

6 0

3 years ago

In an aqueous solution, 42% of a substance dissociates to release hydronium ions. Which of the following statements is true for

const2013 [10]

Answer: The statement it is a weak acid is true for the substance.

Explanation:

An acid that dissociates completely when dissolved in water to give hydrogen $(H^{+})$ or hydronium $(H_{3}O^{+})$ ions is called a strong acid.

For example, HCl is a strong acid.

$HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}$

An acid that dissociates partially or weakly when dissolved in water to given hydrogen or hydronium ions is called a weak acid.

For example, $CH_{3}COOH$ is a weak acid.

$CH_{3}COOH \rightleftharpoons CH_{3}COO^{-} + H_{3}O^{+}$

A strong base is a base which when dissolved in water then it dissociates completely to give hydroxide ions.

For example, NaOH is a strong acid.

A weak base is a base which when dissolved in water then it dissociates partially or weakly to give hydroxide ions.

For example, $NH_{3}$ is a weak base.

Hence, in an aqueous solution where 42% of a substance dissociates to release hydronium ions shows that the dissociation is less than 50%. This means that substance is dissociating weakly so, it is a weak acid.

Thus, we can conclude that the statement it is a weak acid is true for the substance.

5 0

2 years ago

Case #4

stiv31 [10]

Answer: 1.) His action is not justified because he could have done something else like talking with someone.

2.) Some of the negative consequences could be Mr. King could lose his job or worse not be able to teach again.

3.) Some other options were having him retake the test or talking to the head of the school, or many other things.

3 0

2 years ago

A 2.00-g sample of a large biomolecule was dissolved in 15.0 g carbon tetrachloride. the boiling point of this solution was dete

Katarina [22]

We will use boiling point formula:

ΔT = i Kb m

when ΔT is the temperature change from the pure solvent's boiling point to the boiling point of the solution = 77.85 °C - 76.5 °C = 1.35

and Kb is the boiling point constant =5.03

and m = molality

i = vant's Hoff factor

so by substitution, we can get the molality:

1.35 = 1 * 5.03 * m

∴ m = 0.27

when molality = moles / mass Kg

0.27 = moles / 0.015Kg

∴ moles = 0.00405 moles

∴ The molar mass = mass / moles
= 2 g / 0.00405 moles
= 493.8 g /mol

5 0

3 years ago