Answer:
1.43 * 10^-2
Explanation:
Firstly, we need to get the ionization equation for lead I chloride. We can then get the Initial, change and equilibrium table of the lead and chloride ions that can help us calculate the molar solubility. This is shown as follows:
PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq)
This shows that one mole of lead ii chloride will yield 1 mole of the lead ion and 2 moles of the chloride ion.
The ICE table is shown below:
Pb2+ 2Cl-
Initial 0.00 0.00
Change +s +2s
Equilibrium s 2s
Ksp = [Pb2+][Cl-]^2
Ksp = [s][2s]^2
Ksp = 4s^3
s^3 = Ksp/4
s = cube.root [Ksp/4]
s = cube.root[1.17 * 10^-5/4]
s = 1.43 * 10^-2
<span>e = mc^2
m = e / c^2
Plug in your numbers in the appropriate units.
</span><span>m=1.02 × 10^-5</span>
Explanation:
Ne 8. S 6. Mg 2. Sn 4. C 4. Al 3. Te 6. Cs 1. Bi 5. Br 7. Ga 3. P 5.
Answer:
42.3moles
Explanation:
The chemical equation given in this question is as follows:
H2 + O2 → H2O
However, this equation is unbalanced, the balanced chemical equation is as follows:
2H2 + O2 → 2H2O
This equation shows that;
2 moles of hydrogen gas (H2) will produce 2 moles of water (H2O)
Hence, If 42.3 moles of water (H2O) are produced, 42.3 × 2/2
= 42.3moles of hydrogen was reacted.
Answer:
Substance S is GLYCEROL.
Explanation:
To know what substance S represent, let us determine the density of substance S.
From the question given above, the following data were obtained:
Mass of S = 92.09 g
Volume of S = 73.09 mL
Density of S =..?
Density = mass /volume
Density of S = 92.09/73.09
Density of S = 1.26 g/mL
Finally, we shall determine what substance S represent as follow:
Comparing the density of substance S (i.e 1.26 g/mL) with those given in question above, substance S is GLYCEROL.
