Calculate the energy required to produce 6.0 moles of Cl2O7 using the following reaction 2 Cl2 + 7 O2 + 130kcal -> 2 Cl207
1 answer:
Answer:
455 Kcal
Explanation:
2Cl2(g) + 7O2(g) + 130kcal → 2Cl2O7(g)
Rearranging we get,
2Cl2(g) + 7O2(g) → 2Cl2O7(g) Δ H = 130 kcal . mol⁻¹
So for per mol reaction will be as above.
In case of 7 mols of product, we need 7/2 mole ratio x 130 = 455 Kcal
You might be interested in
The answer to this question I think would be 2: Better
Answer:
HPO42- (aq) + NH4+ (aq)
Explanation:
This is a conjugate acid-base pair. Please forgive if my answers are incorrect. I myself am quite unsure.
Sw ocjhohz hug tú the funny ohhzubutgrrfuY
Answer:
2
Explanation:
In the equation, Cl is chlorine and there is a number "2" so that the correct answer is 2.
Answer:
the second one is it.
Explanation:
