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weeeeeb [17]
2 years ago
6

A bathtub contains 12 gallons of water. With these 12 gallons, the bathtub is only 30% full. How many gallons of water can the b

athtub hold when it is completely full?
Mathematics
1 answer:
Pachacha [2.7K]2 years ago
6 0

Answer:

40 gallons

Step-by-step explanation:

Let the number of gallons that would completely fill the bathtub be represented by N.

Since 12 gallons of water gives 30% of the number of gallons to fill the bathtub, then;

30% of N = 12

\frac{30}{100} x N = 12

30N = 12 x 100

30N = 1200

divide both sides by 30,

N = \frac{1200}{30}

   = 40

The number of gallons that would completely fill the bathtub is 40 gallons.

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2.6.4 practice algebra 2 you are helping to design a road for a high mountain pass. there are two routes over the pass, but both
lora16 [44]

Answer:

Step-by-step explanation:

8 0
3 years ago
I need help with both of these questions please
tankabanditka [31]

Answer:

\frac{22}{30} = \frac{11}{15}

and

\frac{176}{7} = 25 \frac{1}{7}

Step-by-step explanation:

First make all the fractions into improper fractions

1\frac{5}{6} = \frac{11}{6} \\\\2\frac{1}{2} = \frac{5}{2} \\\\3\frac{1}{7} = \frac{22}{7}

After doing that put them back into the problems

Problem 1)

1\frac{5}{6}  ÷ 2\frac{1}{2} , plug in the improper fractions

\frac{11}{6} ÷ \frac{5}{2}

to divide, you need to flip the second fraction and multiply

\frac{11}{6}· \frac{2}{5} = \frac{22}{30}

then reduce

\frac{22}{30} = \frac{11}{15}

Problem 2)

3\frac{1}{7}÷ \frac{1}{8}\\

Plug in improper fraction

\frac{22}{7} ÷ \frac{1}{8}\\

Then flip second fraction and multiply

\frac{22}{7} · \frac{8}{1}

Multiply

\frac{176}{7}

Reduce, or make it a mixed number

\frac{176}{7} = 25 \frac{1}{7}

3 0
3 years ago
Simplify 14a over 15 Plus 2a + 36 over 5​
Yuliya22 [10]

Answer:

(20a+108)/15

Step-by-step explanation:

First find LCM of the denominators. U will find it to be 15

Then calculate the number like this.

[(14a)×1/15×1]+[(2a+36)×3/5]

[(14a/15)]+[(6a+108)/15

(14a+6a+108)/15

(20a+108)/15

5 0
3 years ago
Common factors of 56 and 70
Colt1911 [192]
The common factors are 14,7,2,1
7 0
3 years ago
Angela took a general aptitude test and scored in the 83rd percentile for aptitude in accounting.
tigry1 [53]

Answer:

(a) 83% of the scores were at or below her score.

(b) 17% was above her score.

Step-by-step explanation:

Given that:

Percentile score of Angela in the general aptitude test = 83rd percentile

To find:

a) Percentage of scores which were at or below her score?

b) Percentage of score which were above her score?

Solution:

First of all, let us learn about the term "<em>Percentile</em>"

Percentile is the value below which the certain percent of people/marks fall.

Therefore, when we say percentile of someone's score is x, then there are x\% of scores are at the same level or below.

And (100-x)\% of the scores are above this level.

Therefore, we can say that:

83% of the scores were at the same level or below the score of Angela.

And (100-83)\% = 17\% of the scores were above the score of Angela.

7 0
3 years ago
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