Assume that the length of the rectangle is "l" and that the width is "w".
We are given that:
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15
Substitute with w in equation I to get the length as follows:
l = 2w + 1
l = 2(15) + 1
l = 30 + 1 = 31
Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
Y=4 on the first one
A=92 on the second one
You want an estimate, not an actual answer. But just in case you think that way, the actual answer is 34/8 - 16/3 - 14/9 = -2 23/36
34/8 = about 4 3/4
16/3 = about 5 1/3
14/9 i= about 1 5/9
So the answer is about 5 - 5 - 1 1/2 which is about (- 1 1/2) That's your answer. Remember you are estimating. I don't know that you can get it much closer without using a calculator.
It does if the x values don't repeat it they repeat it doesn't
Trick question: none, as i can do 600 or 606, etc
