Answer:
Explanation:
Following relation exists between number of turns and volt
Volt in primary / volt in secondary = no of turns in primary / no of turns in sec
19000 / 120 = no of turns in primary / 159
no of turns in primary = 19000 x 159 / 120
= 25175 Ans .
Answer: 17 m/s
Velocity and acceleration are vector quantities. Let leftwards be defines as negative and rightwards as positive direction.
It is given that canoe is drifting left with a velocity of 
The canoe rider is moving towards right with a constant acceleration, 
we need to find the velocity of canoe after 4 s.
we will use the equation of motion:

where, v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
Insert the values in the above equation:

Hence, velocity of canoe after 4 s would be 17 m/s.
Answer:
dI/dt = 0.0004 A/s
Explanation:
R = 600 ohms
I = 0.04 A
dR/dt = -0.5 ohms/s
dV/dt = 0.04 V/s
From Ohm's law V = IR
Taking the derivative of both sides with respect to t using product rule
dV/dt = I dR/dt + R dI/dt
0.04 = -( 0.04*0.5) + (600) dI/dt
0.04 + 0.2 = 600 dI/dt
0.24 = 600 dI/dt
dI/dt = 0.24/600
dI/dt = 0.0004 A/s
Answer:
Tying a 4 weight pound on a string is a potential energy because it is at rest but cutting it and letting it fall experiences a kinetic energy because it will be in motion.
<h2>
<u>Given</u>:</h2>
Horizontal distance between two boats = x = 14 m
One boat is at trough, the other is at crest.
As there is no crests between them meaning the boat are next to each other.
Wavelength is the distance between two consecutive crests/troughs = w
The distance between a crest and a trough next to it = w/2
Complete cycles = c = 5
Time taken for c cycles = t = 15 s
Vertical distance between two boats = y = 2.4 m
<h2>
<u>To find</u>:</h2>
wavelength = w = 2x = 28 m
Amplitude = A = Displacement from mean to extreme position = y/2 = 1.2 m
Time period for one cycle = T = t/c = 15/5 = 3 s/cycle
frequency = 1/T = 1/3 = 0.33 hertz
speed = wavelength/Period = w/T = 28/3 = 9.33 m/s