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Ulleksa [173]
3 years ago
11

A ball travels with velocity given by Error converting from MathML to accessible text., with wind blowing in the direction given

by Error converting from MathML to accessible text. with respect to some co-ordinate axes. What is the magnitude of the velocity of the ball in the direction of the wind

Physics
1 answer:
KengaRu [80]3 years ago
5 0

Answer: The magnitude of the velocity = 2/5 m/s

Explanation:

 In this question, the magnitude of the velocity is the product of the magnitude of the displacement vector and the magnitude of the component of the velocity that acts in the direction of displacement.

This will be a scalar projection of V onto X

Please find the attached files for the solution

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A neighborhood transformer on the top of a utility pole transforms 19.0 kV 60.0 Hz alternating voltage down to 120.0 V to be use
Troyanec [42]

Answer:

Explanation:

Following relation exists between number of turns and volt

Volt in primary / volt in secondary = no of turns in primary / no of turns in sec

19000 / 120 = no of turns in primary / 159

no of turns in primary = 19000 x 159 / 120

= 25175 Ans .

3 0
3 years ago
A canoe is drifting left toward a hungry hippo with a velocity of 7\,\dfrac{\text{m}}{\text{s}}7
IrinaK [193]

Answer: 17 m/s

Velocity and acceleration are vector quantities. Let leftwards be defines as negative and rightwards as positive direction.

It is given that canoe is drifting left with a velocity of u=-7 m/s

The canoe rider is moving towards right with a constant acceleration, a=6 m/s^2

we need to find the velocity of canoe after 4 s.

we will use the equation of motion:

v=u+at

where, v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Insert the values in the above equation:

\Rightarrow v=-7m/s+6 m/s^2 \times 4 s=24m/s-7 m/s=17 m/s

Hence, velocity of canoe after 4 s would be 17 m/s.


3 0
4 years ago
The voltage V in a simple circuit is related to the current I and the resistance R by Ohm's Law: V=IR. An illustration of a simp
LenaWriter [7]

Answer:

dI/dt = 0.0004 A/s

Explanation:

R = 600 ohms

I = 0.04 A

dR/dt = -0.5 ohms/s

dV/dt = 0.04 V/s

From Ohm's law V = IR

Taking the derivative of both sides with respect to t using product rule

dV/dt = I dR/dt + R dI/dt

0.04 = -( 0.04*0.5) + (600) dI/dt

0.04 + 0.2 = 600 dI/dt

0.24 = 600 dI/dt

dI/dt = 0.24/600

dI/dt = 0.0004 A/s

4 0
3 years ago
Read 2 more answers
Help with Physical Science! I have to do this discussion on potential and kinetic energy. The example of the problem is a 4 poun
algol [13]

Answer:

Tying a 4 weight pound on a string is a potential energy because it is at rest but cutting it and letting it fall experiences a kinetic energy because it will be in motion.

8 0
4 years ago
Two boats are anchored in the harbor, separated by a horizontal distance of 18 m. The boats bob up and down as waves enter the h
sineoko [7]
<h2><u>Given</u>:</h2>

Horizontal distance between two boats = x = 14 m

One boat is at trough, the other is at crest.

As there is no crests between them meaning the boat are next to each other.

Wavelength is the distance between two consecutive crests/troughs = w

The distance between a crest and a trough next to it = w/2

Complete cycles = c = 5

Time taken for c cycles = t = 15 s

Vertical distance between two boats = y = 2.4 m

<h2><u>To find</u>:</h2>

wavelength = w = 2x = 28 m

Amplitude =  A = Displacement from mean to extreme position = y/2 = 1.2 m

Time period for one cycle = T = t/c = 15/5 = 3 s/cycle

frequency = 1/T = 1/3 = 0.33 hertz

speed = wavelength/Period = w/T = 28/3 = 9.33 m/s

4 0
3 years ago
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