1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
otez555 [7]
3 years ago
11

How much work in joules is required to lift a 23 kg box up from the ground to your waist that is 1.0 meters high, carry it 6 met

ers horizontallyy across the room and place it on a shelf that is 5.7 meters off the ground? Do not type units. Round your answer to te tnths place
Physics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

2682

Explanation:

Work done is given by :

Work = Force x distance

         =  mg x d

So, work done in lifting the box of 23 kg up to my waist of 1 m high is :

W = mg x d

   = 23 x 9.18 x 1

   = 211.14

Now work done carrying the box horizontally 6 meters across the room is

W = mg x d

   = 23 x 9.18 x 6

   = 1266.84

Work done in placing the box on the shelf that is 5.7 m above the ground is

W = mg x d

   = 23 x 9.18 x 5.7

   = 1203.49

So the total work done is = 211.14 + 1266.84 + 1203.49

                                          = 2681.47

                                          = 2682 (rounding off)

You might be interested in
a 12000.0-kg car is traveling at 19 m/s. the driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic
tensa zangetsu [6.8K]
What I don’t get it ?
6 0
3 years ago
How is NASA a catalyst to make the crew work better?
spin [16.1K]

Answer:

with teamwork

Explanation:

you need to use team work so the right answer is C

7 0
3 years ago
What is the difference between charging by contact and charging by induction in terms of electron transfer.
Veronika [31]

Answer:

the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch

Explanation:

There are three methods of charging an object:

- Charging by friction: this is done by rubbing an object against another object. An example is when a plastic rod is rubbed with a wool cloth. When this is done, electrons are transferred from the wool to the rod, so both objects remain charged at the end of the process

- Charging by contact: this is done by putting in contact a charged object with a neutral, conducting object. In this case, the charges are transferred from the charged object to the neutral object; at the end of the process, the neutral object will also have a net electric charge, so it will be also charged.

- Charging by induction: in this case, we take a charged object, and a neutral object, and we place the two objects close to each other, but without touching. Let's assume that the charged object is negatively charged: in this case, the positive charges in the neutral object are attracted towards the negative charges of the charged object, while the negative charges of the neutral object are repelled away. As a result, the positive and negative charges in the neutral object split apart. If the object is connected to the ground, then negative charges move away, so the neutral object will remain positively charged.

Therefore, the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch.

5 0
3 years ago
A ball is thrown upward at a 45∘∘ angle. In the absence of air resistance, the ball follows a_________. A. A ball is thrown upwa
enot [183]

Answer:

C. parabolic Curve

Explanation:

The trajectory of a projectile motion is parabolic.

If a ball is thrown at angle of 45° to the horizontal then it will follow a parabolic curve during its motion as its a projectile motion. The other options are incorrect as sine curve is a periodic type of curve. linear curve and tangential curve are also out of place.So option C is correct

8 0
3 years ago
An ac voltage, whose peak value is 250 V , is across a 330-Ω resistor. Part A What is the peak current in the resistor?
Wittaler [7]

Answer:

Peak current is 0.75 A

RMS voltage is 176.77 V

RMS current is 0.53 A

Explanation:

Peak current is

I=\frac{V}{R} \\\\I=\frac{250}{330}\\I=0.75 A

RMS voltage is

V_{RMS}=\frac{V}{\sqrt{2} } \\V_{RMS}=\frac{250}{\sqrt{2} }\\V_{RMS}=176.77 V

RMS current is

I_{RMS}=\frac{V_{RMS}}{R} \\I_{RMS}=\frac{176.77}{330} \\I_{RMS}=0.53 A

7 0
3 years ago
Other questions:
  • A cube has sides of 11.4 cm. What is its volume? 1,482 cm3 130 cm3 1,443 cm3 34.2 cm3
    10·1 answer
  • You have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3
    7·1 answer
  • What is the motion of the negative electrons and positive atomic nuclei caused by the external field?
    8·1 answer
  • At a certain time a particle had a speed of 48 m/s in the positive x direction, and 4.5 s later its speed was 92 m/s in the oppo
    9·1 answer
  • Ent Cards<br> 4.Q: True or False? Anotherword for<br> tube is "duct."<br> A:<br> Explanation:
    12·1 answer
  • How do intensity, frequency, and time affect physical fitness?
    5·1 answer
  • Draw a standard VOLLEYBALL COURT to show the correct player’s positioning and rotation by writing the numbers of each player.
    9·1 answer
  • What are the laws of motion​
    12·2 answers
  • In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background sign
    6·1 answer
  • When a car moves up a hill with constant
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!