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3 years ago

What is the mass of 3.5 mol of MgBr2?

Chemistry

1 answer:

MaRussiya [10]3 years ago

5 0

Answer:

The answer is 0.0054314469917931.

Explanation:

I assume you are converting between moles MgBr2 and gram. You can view more details on each measurement unit: molecular weight of MgBr2 or grams This compound is also known as Magnesium Bromide.

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attashe74 [19]

Independent Variable: amount of sunlight given

Dependent Variable: How tall the plants grow

Control: The plant given no sunlight

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4 years ago

Please help with number 24

vladimir1956 [14]

Layla it is A. that's the only one in standard form.

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3 years ago

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Which of the following is a chemical change?I

Sergeu [11.5K]

Answer:

combustion is a chemical change

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3 years ago

How many atoms of hydrogen are in 0.56 mol of (NH4)2SO4

BabaBlast [244]

<h2>Answer: $2.7\times 10^{24}$ atoms</h2>

Explanation:

The given formula of the compound is $(NH_{4})_{2}SO{4}$

The formula says

Every mole of $(NH_{4})_{2}SO{4}$ contains $8$ moles of atoms of hydrogen.

Given that number of moles of compound is $0.56$

So,the number of moles of hydrogen atoms present is $0.56\times 8=4.48$

Since each mole has $6.022\times 10^{23}$ atoms,

$4.48$ moles has $4.48\times 6.022\times 10^{23}=2.7\times 10^{24}$ atoms.

7 0

3 years ago

A 222 N force is required to keep an object moving along a circular path with a diameter of 11.6 m at a speed of 7.60 m/s. What

Arte-miy333 [17]

Answer:

$m=22.3\ kg$

Explanation:

The expression for centrifugal force is shown below as:-

$F=\frac{m\times v^2}{r}$

Where, m is the mass of the object = ?

v is the velocity of the object = 7.60 m/s

r is the radius

F is the force = 222 N

Diamter = 11.6 m

Radius = d/2 = 11.6 m/2 = 5.8 m

Applying the values in the above expression as:-

$222=\frac{m\times {7.60}^2}{5.8}$

$57.76m=1287.6$

$m=22.3\ kg$

7 0

3 years ago