Ask question

Ask question

All categories

2 years ago

8

The ratio of side lengths of a quadrilateral is 3 : 5 : 6 : 9, and its perimeter is 9.2cm. What is the length of the longest sid

e?

1 answer:

wolverine [178]2 years ago

5 0

Answer:

longest side=3.6

let ratio 3:5:6:9be 3x,5x,6xand9x

perimeter= sum of all side

9.2=3x+5x+6x+9x

9.2=23x

x=9.2÷23

x=0.4

9x=9×0.4=3.6

6x=6×0.4=2.4

5x=5×0.4=2

3x=3×0.4=1.2

You might be interested in

Please help me with this i’m stuck

bagirrra123 [75]

Answer:

A ) Substitute the side lengths of a and b in the equation

Step-by-step explanation:

The hypotenuse which is opposite the right angle it always the length of C in the cosine rule.

5 0

3 years ago

What is the arc length of the subtending arc for an angle of 72 degrees on a circle of radius 4?

wolverine [178]

Step-by-step explanation:

We can set up the ration of the radian angle θ in your problem in terms of degrees given as the ratio: (Θ/2·pi) = (72/360), solving for Θ we get Θ = 1.26 radians. Then for the arc length s = Θ·r using this value gives s = 1.26·4 = 5.04

7 0

3 years ago

Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.

leonid [27]

If

$\displaystyle g(x) = \int_0^x f(t) \, dt$

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

$\displaystyle g(0) = \int_0^0 f(t) \, dt = 0$

since the integral of any function over a single point is zero;

$\displaystyle g(4) = \int_0^4 f(t) \, dt = 8$

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

$\displaystyle g(8) = \int_0^8 f(t) \, dt = 0$

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

$\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8$

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

$\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0$

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

$\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24$

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

$\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64$

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0

3 years ago

Evaluate: 6 plus x squared times 2 for x = 4

Mkey [24]

$4^{2} = 16$

16 times 2 = 32

32 plus 6 = 38

always remember PEMDAS

3 0

3 years ago

The graph of g(x) is a transformation of the graph of f(x)=2x. Enter the equation for g(x) in the box. g(x) =

Lunna [17]

<h3>Answer: $g(x) = 2^x - 3$ </h3>

The -3 is not in the exponent

Explanation:

The parent function is $f(x) = 2^x$ . Plugging in x = 0 leads to y = 1. So the point (0,1) is on the f(x) curve. Going from (0,1) to (0,-2) is a vertical shift of 3 units downward. To represent this shift, we tack on a "-3" at the end of the f(x) function.

$g(x) = f(x) - 3\\\\g(x) = 2^x - 3$

You could look at other points as well, but I find working with x = 0 is easiest.

As a check, plugging x = 0 into g(x) leads to...

$g(x) = 2^x - 3\\\\g(0) = 2^0 - 3\\\\g(0) = 1 - 3\\\\g(0) = -2$

This confirms our answer.

4 0

3 years ago