1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FrozenT [24]
3 years ago
13

URGENT

Physics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

give \\ mass(m) = 1350kg  \\ acceleration(a) = 1ms {}^{ - 2}  \ \\ sln\ \\  from \: our \: formula \\  \: f = ma \\1350kg \times 1ms {}^{ - 2}  \\ f = 1350newton

the force you applied to your car =1350N

You might be interested in
If the velocity of blood flow in the aorta is normally about 0.32 m/s, what beat frequency would you expect if 4.40-MHz ultrasou
dusya [7]

Answer:

The beat frequency is 0.0019 MHz.

Explanation:

Given that,

Velocity = 0.32 m/s

Frequency = 4.40 MHz

Speed of wave = 1540 m/s

We need to calculate the frequency

Case (I),

Observer is moving away from the source

Using Doppler's effect

f'=\dfrac{v-v'}{v}f

Where, v' = speed of observer

Put the value into the formula

f'=\dfrac{1540-0.32}{1540}\times4.40

f'=4.399\ MHz

Case (II),

Cell is as the source of sound of frequency f' and it moving away from the observer.

Using formula of frequency

f''=\dfrac{v-v_{s}}{v+v_{s}}\times f

f''=\dfrac{1540-0.32}{1540+0.32}\times4.399

f''=4.3971\ MHz

We need to calculate the beat frequency

\Delta f= f'-f''

\Delta f=4.399-4.3971=0.0019\ MHz

Hence, The beat frequency is 0.0019 MHz.

4 0
3 years ago
An ideal photo-diode of unit quantum efficiency, at room temperature, is illuminated with 8 mW of radiation at 0.65 µm wavelengt
nadya68 [22]

Answer:

I = 4.189 mA    V = 0.338 V

Explanation:

In order to do this, we need to apply the following expression:

I = Is[exp^(qV/kT) - 1]   (1)

However, as the junction of the diode is illuminated, the above expression changes to:

I = Iopt + Is[exp^(qV/kT) - 1]   (2)

Now, as the shunt resistance becomes infinite while the current becomes zero, we can say that the leakage current is small, and so:

I ≅ Iopt

Therefore:

I ≅ I₀Aλq / hc  (3)

Where:

I₀A = Area of diode (radiation)

λ: wavelength

q: electron charge (1.6x10⁻¹⁹ C)

h: Planck constant (6.62x10⁻³⁴ m² kg/s)

c: speed of light (3x10⁸ m/s)

Replacing all these values, we can get the current:

I = (8x10⁻³) * (0.65x10⁻⁶) * (1.6x10⁻¹⁹) / (6.62x10⁻³⁴) * (3x10⁸)

I = 4.189x10⁻³ A or 4.189 mA

Now that we have the current, we just need to replace this value into the expression (2) and solve for the voltage:

I = Is[exp^(qV/kT) - 1]

k: boltzman constant (1.38x10⁻²³ J/K)

4.189x10⁻³ = 9x10⁻⁹ [exp(1.6x10⁻¹⁹ V / 1.38x10⁻²³ * 300) - 1]

4.189x10⁻³ / 9x10⁻⁹ = [exp(38.65V) - 1]

465,444.44 + 1  = exp(38.65V)

ln(465,445.44) = 38.65V

13.0508 = 38.65V

V = 0.338 V

6 0
3 years ago
HURRY PLEASE!!!
REY [17]
90for each walk because 6• 15 = 90
8 0
3 years ago
Read 2 more answers
I really don’t know what it is to me they r all the same
Inessa05 [86]
The moon lacks an atmosphere compared to the Earth. Hope this helps!
4 0
3 years ago
Read 2 more answers
It is claimed that if a lead bullet goes fast enough, it can melt completely when it comes to a halt suddenly, and all its kinet
TEA [102]

Answer:

v=346.05\ m.s^{-1}

Explanation:

Given:

initial temperature of the lead bullet, T_i=43^{\circ}C

latent heat of fusion of lead, L_f=2.32\times 10^4\ J.kg^{-1}

melting point of lead, T_m=327.3^{\circ}C

We have:

specific heat capacity of lead, c=129\ J.kg^{-1}.K^{-1}

<em>According to question the whole kinetic energy gets converted into heat which establishes the relation:</em>

\rm KE=(heat\ of\ rising\ the\ temperature\ from\ 43\ to\ 327.3\ degree\ C)+(heat\ of\ melting)

\frac{1}{2} m.v^2=m.c.\Delta T+m.L_f

\frac{1}{2} m.v^2=m(c.\Delta T+L_f)

\frac{v^2}{2} =129\times(327.3-43)+23200

v=346.05\ m.s^{-1}

3 0
3 years ago
Other questions:
  • Physics Question, Please Help:
    11·1 answer
  • Which type of star has surface temperatures bewteen 2400 and 50000 k
    13·1 answer
  • Julia produces a 2 mA current by moving the south pole of a bar magnet into a solenoid. The solenoid contains 150 loops of wire.
    9·2 answers
  • With which field of science is Albert Einstein associated? biology chemistry medecine physics
    8·2 answers
  • A frictionless pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet, the length of the pendulu
    6·1 answer
  • What happens to an atom of a particular element if it somehow loses a proton?
    14·2 answers
  • A wave produced by a doorbell
    15·1 answer
  • Which of the following is the most appropriate definition of organic compound?
    9·2 answers
  • Một electron di chuyển theo đường tròn vuông góc với từ trường đều 1mT. Moment động lượng của electron đối với tâm vòng tròn là
    9·1 answer
  • If a swimmer is swimming 200m at 4 m/s how long would it take them to complete the race
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!