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maw [93]
3 years ago
6

Compare and contrast series and parallel circuits?

Physics
1 answer:
dalvyx [7]3 years ago
6 0

In a series circuit, a common current flows through all the components of the circuit. While in a parallel circuit, a different amount of current flows through each parallel branch of the circuit. Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.

Hope It Helps!

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According to the reading, which of the following is NOT an obstacle to using big data for analysis and decision making? O Poor r
RoseWind [281]

Answer:

B .Limited types of data Insufficient data

Explanation:

To analyse and making decision from big data we have following thing

- Sufficient data

- data analyst

- Accurate data

- data Privacy

- data storage

So, limited data or data that cannot be copied is not and obstacle in data handling. hence option B Limited types of data Insufficient data is correct.

3 0
4 years ago
A small rock is launched straight upward from the surface of a planet with no atmosphere. The initial speed of the rock is twice
Scorpion4ik [409]

If gravitational effects from other objects are negligible, the speed of the rock at a very great distance from the planet will approach a value of \sqrt{3} v_{e}

<u>Explanation:</u>

To express velocity which is too far from the planet and escape velocity by using the energy conservation, we get

Rock’s initial velocity , v_{i}=2 v_{e}. Here the radius is R, so find the escape velocity as follows,

            \frac{1}{2} m v_{e}^{2}-\frac{G M m}{R}=0

            \frac{1}{2} m v_{e}^{2}=\frac{G M m}{R}

            v_{e}^{2}=\frac{2 G M}{R}

            v_{e}=\sqrt{\frac{2 G M}{R}}

Where, M = Planet’s mass and G = constant.

From given conditions,

Surface potential energy can be expressed as,  U_{i}=-\frac{G M m}{R}

R tend to infinity when far away from the planet, so v_{f}=0

Then, kinetic energy at initial would be,

                  k_{i}=\frac{1}{2} m v_{i}^{2}=\frac{1}{2} m\left(2 v_{e}\right)^{2}

Similarly, kinetic energy at final would be,

                k_{f}=\frac{1}{2} m v_{f}^{2}

Here, v_{f}=\text { final velocity }

Now, adding potential and kinetic energies of initial and final and equating as below, find the final velocity as

                 U_{i}+k_{i}=k_{f}+v_{f}

                 \frac{1}{2} m\left(2 v_{e}\right)^{2}-\frac{G M m}{R}=\frac{1}{2} m v_{f}^{2}+0

                  \frac{1}{2} m\left(2 v_{e}\right)^{2}-\frac{G M m}{R}=\frac{1}{2} m v_{f}^{2}

'm' and \frac{1}{2} as common on both sides, so gets cancelled, we get as

                   4\left(v_{e}\right)^{2}-\frac{2 G M}{R}=v_{f}^{2}

We know, v_{e}=\sqrt{\frac{2 G M}{R}}, it can be wriiten as \left(v_{e}\right)^{2}=\frac{2 G M}{R}, we get

                4\left(v_{e}\right)^{2}-\left(v_{e}\right)^{2}=v_{f}^{2}

                v_{f}^{2}=3\left(v_{e}\right)^{2}

Taking squares out, we get,

                v_{f}=\sqrt{3} v_{e}

4 0
3 years ago
The heat transfer depicted in the image is MOST likely
stealth61 [152]

Answer:

Convection

Explanation:

 

8 0
4 years ago
Read 2 more answers
How does the speed ratio change as you switch between different gears on a bicycle, and how does this affect the force you need
FromTheMoon [43]

An average cyclist generates about 183 watts while doing 19 mph or 30.4 kph. Power = force × velocity. Force of a pedalling applied by a human for achieving 30.4 kph = 183/8.44 = 21.68 newtons. This is for upright bicycles.

7 0
3 years ago
A 4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment,
Stella [2.4K]
<span>the body is moving horizontally, it doesnt matter watever kind of horizontal forces are acting.
 Therefore the normal force is equal to the weight
 N=mg=4.2*9.8=41N
 Note: the other data in the problem have no relevance
 answer
</span> the normal force on the sled is 41N 
6 0
4 years ago
Read 2 more answers
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