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mario62 [17]
3 years ago
5

Which of the following blackbody curves is representative of stars like our Sun?

Chemistry
1 answer:
Xelga [282]3 years ago
3 0

Answer:

its letter b

Explanation:

it represents the spectrum of stars

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Formular for solubility​
Komok [63]

Answer:

= konstanta produk kelarutan

= kation dalam larutan berair

= anion dalam larutan berair

= konsentrasi relatif a dan b

DARI WEB

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g . Solubility of NaNO3=21.9g or NaNO3 x 100 g/ 25 g =87.6. Calculate the molar mass of the dissolved compound as the sum of mass of all atoms in the molecule.

6 0
3 years ago
Read 2 more answers
Here is the electron configuration for Magnesium. How many total electrons are in the 2nd energy level?
balandron [24]

Answer:

8 electrons

Explanation:

Magnesium is present on group 2.

It has 2 valence electrons.

Electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

1st energy level contain 2 electrons.(1s²)

2nd energy  level contain 8 electrons. (2s² 2p⁶)

3rd energy level contain 2 electrons. (3s²)

3rs energy level of magnesium is called valence shell. It contain two valance electrons. Magnesium can easily donate its two valance electrons and get stable electronic configuration.

It react with halogens and form salt. For example,

Mg + Cl₂   →   MgCl₂

7 0
3 years ago
A student places a 12-gram cube of ice inside a container. After six hours, the student returns to observe the contents of the c
jok3333 [9.3K]

Answer:

The answer is c

Explanation:

Because all of the Other ones did not make sense

7 0
3 years ago
During an investigation, a student burns magnesium to form magnesium oxide. The starting mass of magnesium is measured as 21.3 g
enot [183]

Answer:

Percentage yield = 85.2%

Explanation:

Given data:

Mass of Mg = 21.3 g

Actual yield of MgO = 30.2 g

Percentage yield = ?

Solution:

Chemical equation:

2Mg + O₂ → 2MgO

Number of moles of Mg = mass/molar mass

Number of moles of Mg = 21.3 g / 24.3 g/mol

Number of moles of Mg = 0.88 mol

Now we will compare the moles of MgO with Mg.

                 Mg           :               MgO

                 2               :               2

                0.88             :             0.88

Mass of MgO:           

Mass of MgO= moles × molar mass

Mass of MgO= 0.88 mol × 40.3g/mol

Mass of MgO =  35.46 g

Actual yield of MgO = 30.2 g

Percentage yield:

Percentage yield = Actual yield/theoretical yield × 100

Percentage yield = 30.2 g/ 35.46 g × 100

Percentage yield = 85.2%

3 0
4 years ago
Find the no. Of electron involved in the electro deposition of 63.5g of cu from a solution of cuso4
sp2606 [1]
This is a redox reaction, meaning reduction-oxidation reaction. This represents the reaction in one side of the electrode in an electrolysis set-up. First, we find the oxidation number of Cu in CuSO4:

(ox. # of Cu)+ ox.# of S + 4(ox.# of oxygen) = 0
(ox. # of Cu) + (6) + 4(-2) = 0
ox. # of Cu = 2+

CuSO4 ---> Cu + SO42-
Cu2+ + SO42-  ---->  Cu + SO42-
Cu2+ -----> Cu + 2e-   (net ionic reaction)

The stoichiometric equation would be 2 electrons per mole Copper. Copper has a molar mass of <span>63.5 g/mol. Then, it would only need 2 electrons.


</span>
8 0
3 years ago
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