All categories

4 years ago

When steam is passed through red hot coke, a mixture of two gases is formed. Explain with reaction

Chemistry

1 answer:

Alenkasestr [34]4 years ago

3 0

Answer:

C(s) + H2O(g) → CO(g) + H2(g)

Explanation:

Carbon monoxide and hydrogen. Possibly some reaction products from impurities in the coke, but mostly CO and H2.

You might be interested in

32. At the left of a chemical equation are the………

Alex777 [14]

Answer:

reactants

Explanation:

3 0

3 years ago

a car manufacturer claims that since their car engines dont get very hot, more of the gasolines energy can be used to make the c

ivanzaharov [21]

Newton’s 2nd law? Maybe I’m not completely sure

7 0

4 years ago

Which answer below correctly identifies the type of change and the explanation for the boiling of water?

Charra [1.4K]

Answer:

Physical change because even though gas formation was observed, the water was undergoing a state change, which means that its original properties are preserved.

Explanation:

The gas formation seen is in fact the transition of the liquid water to a gas state, not the formation of a new gas.

8 0

3 years ago

Read 2 more answers

A charged atom or particle is a(n) _____. compound ion neutron valence

mel-nik [20]

This would be an ion

Hope this helps :)

4 0

4 years ago

If 0.40 mol of H2 and 0.15 mol of O2 were to react as completely as possible to produce H2O what mass of reactant would remain?

liberstina [14]

Answer : The mass of reactant $H_2$ remain would be, 0.20 grams.

Solution : Given,

Moles of $H_2$ = 0.40 mol

Moles of $O_2$ = 0.15 mol

Molar mass of $H_2$ = 2 g/mole

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced reaction we conclude that

As, 1 mole of $O_2$ react with 2 mole of $H_2$

So, 0.15 moles of $O_2$ react with $0.15\times 2=0.30$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

The moles of reactant $H_2$ remain = 0.40 - 0.30 = 0.10 mole

Now we have to calculate the mass of reactant $H_2$ remain.

$\text{ Mass of }H_2=\text{ Moles of }H_2\times \text{ Molar mass of }H_2$

$\text{ Mass of }H_2=(0.10moles)\times (2g/mole)=0.20g$

Therefore, the mass of reactant $H_2$ remain would be, 0.20 grams.

3 0

3 years ago

When steam is passed through red hot coke, a mixture of two gases is formed. Explain with reaction​

When steam is passed through red hot coke, a mixture of two gases is formed. Explain with reaction