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Margarita [4]
3 years ago
11

1.

Chemistry
1 answer:
garik1379 [7]3 years ago
5 0

Explanation:

1.

Given parameters:

Frequency of the radiation  = 8.4 x 10¹⁴Hz

Unknown:

Energy of the wave  = ?

Solution:

The energy of a wave is given by the expression below;

    E  = hf

E is the energy

h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

f is the frequency

 Now insert the parameters and solve;

 E  =  6.63 x 10⁻³⁴m²kg/s x 8.4 x 10¹⁴Hz

 E  = 5.57 x 10¹ x 10⁻²⁰J

 E  = 5.57 x 10⁻¹⁹J

   

2.

Given parameters:

Wavelength = 2.13 x 10⁻¹³m

Unknown:

Frequency of the wave = ?

Solution:

The frequency of a wave can be determined using the expression;

     C  = f∧

C is the speed of light = 3 x 10⁸m/s

f  is the frequency

∧ is the wavelength

      f  = \frac{C}{wavelength}   = \frac{3  x 10^{8} }{2.13 x 10^{-13} }   = 1.41 x 10²¹hz

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Calculate the percent composition of the following:<br><br> A. VO3<br><br> B. V2O5
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A) Answer is: 51.48% V and 48.52% O.

Ar(V) = 50.94; atomic weight of vanadium.

Ar(O) = 16; atomic weight of oxygen.

Ar(VO₃) = 50.94 + 3 · 16.

Ar(VO₃) = 98.94; molecular weight of vanadium (VI) oxide.

ω(V) = Ar(V) ÷ Ar(VO₃) · 100%.

ω(V) = 51.48%; the percent composition of vanadium.

ω(O) = 100% - 51.48%.

ω(O) = 48.52%; the percent composition of oxygen.

B) Answer is: 67.80% V and 32.20% O.

Ar(V) = 50.94; atomic weight of vanadium.

Ar(O) = 16; atomic weight of oxygen.

Ar(V₂O₅) = 2 · 50.94 + 5 · 16.

Ar(V₂O₅) = 149.88; molecular weight of vanadium (V) oxide.

ω(V) = 2 · Ar(V) ÷ Ar(V₂O₅) · 100%.

ω(V) = 67.80%; the percent composition of vanadium.

ω(O) = 100% - 67.80%.

ω(O) = 32.20%; the percent composition of oxygen.

4 0
3 years ago
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