The mass of oxygen gas is released in the reaction of decomposition of magnesium oxide 6.4 grams
calculation
mass of oxygen=mass of magnesium oxide -mass of magnesium produced
that is 16.12-9.72=6.4 grams
<h2>
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Answer:
The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction of ammonia, NH3, with sulfuric acid: 2 NH3 (g) + H2SO4 (aq) (NH4)2SO4 (aq)
How many moles of ammonium sulfate are produced if 1.50 moles of ammonia react completely at STP? Answer: The balanced equation indicates that 2 moles of NH3 react to produce 1 mole of (NH4)2SO4.
1.50 moles NH3 x 1 mol (NH4)2SO4 = 0.750 moles (NH4)2SO4
Explanation:
Answer:
The IUPAC name of given compound is 3−5−ethyl−5−−3−methylheptane. Explanation: The parental chain is of 7 carbons with single bonds hence it is heptane. Two substituents ethyl and methyl group are attached from an equal distance. Hence according to the alphabetical order preference, counting starts from carbon which is close to an ethyl group.
