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____ [38]
3 years ago
15

A horse pulls a cart along a flat road. They start from rest and as time goes on their speed increases. Consider the following f

our forces:
The force of the horse pulling on the cart;

The force of the cart pulling on the horse;

The force of the horse pushing on the road

The force of the road pushing on the horse.

Which of the following statements is true concerning these forces?

Force 2 exceeds force 4.

Force 2 is less than force 3.

Force 3 exceeds force 4.

Forces 1 and 2 cannot have equal magnitudes.

Force 1 exceeds force 2.
Physics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

Forces 1 and 2 cannot have equal magnitudes.

Force 1 exceeds force 2.

Explanation:

Numbering the given statements:

  1. The force of the horse pulling on the cart.
  2. The force of the cart pulling on the horse.
  3. The force of the horse pushing on the road .
  4. The force of the road pushing on the horse.
  • When a horse pulls a cart along a flat road starting from the state of rest, the horse applies a force on the ground in downward-back direction diagonally and as its reaction it moves forward. During this action there is also a reaction force by the road on the horse which exceeds the force of the horse on the ground and as a result the horse moves forward.
  • For pulling the cart the horse applies the force on  the cart  in the forward direction and as a reaction the cart applies a force on the horse in the backward direction which is less than the force of the horse on the cart resulting in the forward motion of the cart along with the horse.

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Your heart pumps blood at a pressure of 100 mmHg and flow speed of 60 cm/s. At your brain, the blood enters capillaries with suc
Savatey [412]

Answer:

1.28 m

Explanation:

Generally, pressure of fluid is given by

P=\rho g h where g is acceleration due to gravity, h is the height and \rho is the density

Considering that the pressure for mercury is same as for blood only that the height and density of fluid are different then

\rho_b g h_b= \rho_m g h_m

Since g is constant, then

\rho_b h_b= \rho_m h_m

Making h_b the subject of the formula then

h_b=\frac {\rho_m h_m}{\rho_b}

Where subscripts m and b denote mercury and blood respectively

Assuming density of blood is 1060 Kg/m3, density of mercury as 13600 Kg/m3 and substituting height of mercury for 0.1 m then

h_b=\frac {13600*0.1}{1060}=1.283018868  m \approx 1.28 m

7 0
3 years ago
Find the magnitude of acceleration (ft/s^2) a person experiences when he or she is texting and driving 58mph, hits a wall, and c
SVEN [57.7K]

Answer:

350 ft/s²

Explanation:

First, convert mph to ft/s.

58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s

Given:

v₀ = 85.1 ft/s

v = 0 ft/s

t = 0.24 s

Find: a

v = at + v₀

a = (v − v₀) / t

a = (0 ft/s − 85.1 ft/s) / 0.24 s

a = -354 ft/s²

Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².

7 0
3 years ago
Before using wind energy to produce electricity, humans used wind energy to produce PLEASE ANSWER QUICKLY
topjm [15]

Answer:

Water

Explanation:

windmills were used to bring water to farms in ancient times.

8 0
3 years ago
Jamal plugged his radio into the wall. The radio's plug had copper wires surrounded by rubber. The rubber protects Jamal from___
Mariana [72]
The rubber protects him from being electrocuted by the flow of current going through the plug.
Hope this helped!!
3 0
3 years ago
Read 2 more answers
A car stops in 130 m. If it has an acceleration of -5 m/s2 what was the cars starting velocity?
Tatiana [17]

Answer:

<u>We are given:</u>

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

<u>Solving for initial velocity:</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

8 0
3 years ago
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