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slavikrds [6]
3 years ago
11

On Planet Y, which has no air, a dropped object falls 9 m in 3 seconds. What is g, the acceleration due to gravity, on that plan

et?
9.8 m/s2

9.8 m/s 2

3 m/s2

2 m/s2
Physics
1 answer:
slavikrds [6]3 years ago
8 0

Answer: time to fall | 2.5 seconds

final speed | 24 m/s (meters per second)

= 1300 miles per day

= 55 mph (miles per hour)

(assuming point mass)

Explanation:

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A car is initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at
Aleks04 [339]
Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
                     = 37.5 m/s
velocity initial = 35 km/hr x  1hr /3600 s x 1000 m/1 km
                      =  9.72 m/s
a) acceleration = 2.646 m/s^2
b) acceleration in g units  = (2.646m/s^2)/(9.8m/s^2)
                                              = 0.27 units

6 0
4 years ago
The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?
ikadub [295]

Answer:

The energy stored in the capacitor quadruples its original value.

Explanation:

The energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the voltage across the plates

The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.

Instead, in this problem the voltage applied is doubled:

V' = 2V

So the new energy stored is

U'=\frac{1}{2}C(2V)^2=4(\frac{1}{2}CV^2)=4U

so, the energy stored has quadrupled.

8 0
3 years ago
A submerged submarine is stationary. The engines are put on maximum power. The submarine moves forward. The engines maintain max
densk [106]
This is EXACTLY the same scenario as the skydiver jumping
out of the airplane, except the whole thing is turned on its side.

==> The skydiver leaves the airplane.
The force of gravity on him (his weight) makes him accelerate down.
But the air resists his downward motion.
The faster he falls, the more UPWARD force the air exerts on him.
The more upward force the air exerts, the less he accelerates down.
When his falling speed is great enough, he stops accelerating, and
falls with a constant speed.  He calls that speed his 'terminal velocity'. 

==> The submarine turns on its engines, at maximum power.
The force of the engines makes the sub accelerate forward. 
But the water resists its forward motion.
The faster it moves, the more BACKWARD force the water exerts on it.
The more backward force the water exerts, the less it accelerates forward.
When the forward speed is great enough, it stops accelerating, and moves
with a constant speed.  I don't know if they use the same term in submarines,
but you might say that speed is the 'terminal velocity' in water. 
3 0
3 years ago
On a cold day, the temperature often feels colder due to a wind chill. This is an
4vir4ik [10]

Answer:

Thermal conduction is the transfer of internal energy by microscopic collisions of particles and movement of electrons within a body. The colliding particles, which include molecules, atoms and electrons, transfer disorganized microscopic kinetic and potential energy, jointly known as internal energy. 

I believe it's conduction

8 0
3 years ago
Cierto volumen de gas se encuentra a 60°c de temperatura y 5atm de presión, es calentado hasta 140°c, estado en el cual ocupa un
earnstyle [38]

Answer:

V1 = 2221.33 L

Explanation:

The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

P_1V_1=nRT_1   (1)

And also for the situation in which the variables T, V and P has changed:

P_2V_2=nRT_2   (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}

Next, you equal these equations an solve for T2:

\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}

Finally you replace the values of P2, V2, T1 and T2:

V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L

Hence, the initial volume of the gas is 2221.33 L

5 0
4 years ago
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