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2 years ago

ILL GIVE BRAINLIEST!!!

Engineering

1 answer:

Sedbober [7]2 years ago

6 0

Get the app socratic I saw the answer to your question on the app but I ran out of screen time to show you

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What is the total inductance of a circuit that contains two 10 uh inductors connected in a parallel?

kolbaska11 [484]

Answer:

5 microhenries

Explanation:

The effective value of inductors in parallel "add" in the same way that resistors in parallel do. The value is the reciprocal of the sum of the reciprocals of the inductances that are in parallel.

10 uH ║ 10 uH = 5 uH

The effective inductance is 5 uH.

6 0

2 years ago

How does the start function make your programs easier to understand?

ad-work [718]

Explanation:

All of the commands you wish to execute must go inside of the start function, between the curly braces.

7 0

3 years ago

Evaluate (204 mm)(0.004 57 kg) / (34.6 N) to three

vesna_86 [32]

Answer:

the evaluation in SI unit will be $2.69\times 10^{-5}sec^{2}$

Explanation:

We have evaluate $\frac{(204mm\times 0.00457kg)}{34.6N}$

We know that 1 mm $=10^{-3}m$

So 240 mm $=204\times 10^{-3}m$

Newton can be written as $kgm/sec^2$

So $\frac{(204\times 10^{-3}m)\times 0.00457kg}{34.6kgm/sec^2}=2.69\times 10^{-5}sec^{2}$

So the evaluation in SI unit will be $2.69\times 10^{-5}sec^{2}$

4 0

3 years ago

A sphere is assumed to have the properties of water and has an initial heat generation 46480 W/m^3 How much should the heat gene

Verdich [7]

Answer:

Resulting heat generation, Q = 77.638 kcal/h

Given:

Initial heat generation of the sphere, $Q_{Gi} = 46480 W/m^{3}$

Maximum temperature, $T_{m} = 360 K$

Radius of the sphere, r = 0.1 m

Ambient air temperature, $T = 25^{\circ}C$ = 298 K

Solution:

Now, maximum heat generation, $Q_{m}$ is given by:

$T_{m} = \frac{Q_{m}r^{2}}{6K} + T$ (1)

where

K = Thermal conductivity of water at $T_{m} = 360 K = 0.67 W/m^{\circ}C$

Now, using eqn (1):

$360 = \frac{Q_{m}\times 0.1^{2}}{6\times 0.67} + 298$

$Q_{m} = 24924 W/m^{3}$

max. heat generation at maintained max. temperature of 360 K is 24924 $W/m^{3}$

For excess heat generation, Q:

$Q = (Q_{Gi} - Q_{m})\times volume of sphere, V$

where

$V = \frac{4}{3}\pi r^{3}$

$Q = (46480 - 24924)\times \frac{4}{3}\pi\0.1^{3} = 21556\times \frac{4}{3}\pi\0.1^{3} W/m^{3}$

$Q = 90.294 W$

Now, 1 kcal/h = 1.163 W

Therefore,

$Q = \frac{90.294}{1.163} = 77.638 kcal/h$

3 0

2 years ago

What does a nuclear reactor smell like... idk im bored.

Lera25 [3.4K]

Answer:

If i had to guess, not the most amazing smell in the world, but i wouldn't know xD

3 0

3 years ago

Read 2 more answers