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Andrews [41]
2 years ago
12

Connect wires to make the correct logic outputs.

Engineering
1 answer:
Aleksandr [31]2 years ago
8 0

Answer:

Explanation:

im dum sorry bro i don't know it im in 6 grade

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If you touch a downed power line, covered or bare, what's the likely outcome?
olya-2409 [2.1K]

Answer:

you get electrocuted...........

5 0
3 years ago
Read 2 more answers
A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 78 MPa (70.98 ksi). If the plate is
Reika [66]

Answer:

minimum length of a surface crack is 15.043 mm

Explanation:

given data

strain fracture toughness K = 78 MPa

tensile stress = 345 MPa

Y = 1.04

to find out

minimum length of a surface crack

solution

we find here length of critical interior flaw from formula that is

α  =  \frac{1}{\pi} (\frac{K}{\sigma Y})^2     ....................1

put here value we get

α  =  \frac{1}{\pi} (\frac{78*\sqrt{10^3} }{345*1.04})^2

α  = 15.043 mm

so minimum length of a surface crack is 15.043 mm

7 0
3 years ago
Which of the following color schemes is composed of hues next to eachother on the color wheel ?
Softa [21]
Analogous color schemes are composed of hues next to each other
3 0
3 years ago
Holmes owns two suits: one black and one tweed. He always wears either a tweed suit or sandals. Whenever he wears his tweed suit
vazorg [7]

Answer:

He wore his black suit, another color of shirt (not purple) and shoes

Explanation:

Holmes owns two suits: one black and one tweed.

Whenever he wears his tweed suit and a purple shirt, he chooses not to wear a tie and whenever he wears sandals, he always wears a purple shirt.

So, if he wore a bow tie yesterday, it means he wore his black suit, another color of shirt (not purple) and shoes because the shirt color is not purple

4 0
3 years ago
The time delay of a long-distance call can be determined by multiplying a small fixed constant by the number of communication li
aliina [53]

Answer:

We can compute the diameter of the tree T by a pruning procedure, starting at the leaves (external nodes).

  • Remove all leaves of T. Let the remaining tree be T1.
  • Remove all leaves of T1. Let the remaining tree be T2.
  • Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
  • When the remaining tree has only one node or two nodes, stop! Suppose now the remaining tree is Tk.
  • If Tk has only one node, that is the center of T. The diameter of T is 2k.
  • If Tk has two nodes, either can be the center of T. The diameter of T is 2k+1.

Explanation:

We can compute the diameter of the tree T by a pruning procedure, starting at the leaves (external nodes).

  • Remove all leaves of T. Let the remaining tree be T1.
  • Remove all leaves of T1. Let the remaining tree be T2.
  • Repeat the "remove" operation as follows: Remove all leaves of Ti. Let remaining tree be Ti+1.
  • When the remaining tree has only one node or two nodes, stop! Suppose now the remaining tree is Tk.
  • If Tk has only one node, that is the center of T. The diameter of T is 2k.
  • If Tk has two nodes, either can be the center of T. The diameter of T is 2k+1.
4 0
3 years ago
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