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3 years ago

A sector has a radius of 4 and a central angle of 40 degrees. Find the arc length and area of sector

Mathematics

1 answer:

g100num [7]3 years ago

4 0

Answer:

Step-by-step explanation:

θ = 2π/9 radians

arc length = rθ = 8π/9 units

area of sector = πr²/9 = 16π/9 square units

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Akio found 18 cents in his pocket. He found 6 more coins in his pocket. Altogether he has 73 cents. What were the 6 coins he fou

Dafna1 [17]

Answer:

1 quarter, 1 dime, and 4 nickels

Step-by-step explanation:

First you subtract the 18 cents that were found in the pocket from the total amount of 73 cents to get the total amount of the 6 other coins:

73-18=55.

So the total amount of the 6 coins equals 55 cents.

The quarter = 25 cents

The dime = 10 cents

The 4 nickels = 5 + 5 + 5 + 5 = 20

1 quarter, 1 dime, and 4 nickels add up to the necessary total of 6 coins and when you add up the total cents of the quarter, dime, and nickels, 25 + 10 + 20 it comes to the sum of 55, which is how much the 6 coins are worth in total.

So therefore, the answer is 1 quarter, 1 dime, and 4 nickels.

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3 years ago

What decimal is equal to 3/10

Aleks [24]

Answer:

0.3

Step-by-step explanation:

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3 years ago

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The stem-and-leaf plot shows the amount of money each student in Spanish club collected for charity this semester. How many male

HACTEHA [7]

72 because I helped you show do you Andreas show me too

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3 years ago

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SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

Find the vertex

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

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3 years ago

Find the measure of ∠2. a. 32 b. 64 c. 116 d. 90

Studentka2010 [4]

Answer:

angle 2 =90 because it is a right angle

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