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sveta [45]
3 years ago
7

What is the combined resistance of 5ohms wire arranged in series with a parallel arrangement of 4ohms and 6ohms wires

Physics
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

This is a very straightforward problem, and not too difficult to do in your head. If we have two nearly equal resistances, the series resistance (Rs) is twice the average value (midpoint between the two) and the parallel resistance Rp) is approximately equal to half the midpoint value. So a rough initial guess might be 12 and 13 ohms, where Rs is 25 ohms but Rp is approximately 6.25 ohms. Since Rp needs to be lower, we can play around with resistor values. Here’s an easy shortcut:

Let’s start with the equation for two parallel resistors:

Rp = (R1 * R2)/(R1 + R2)

Since Rs = R1 + R2,

Rp = (R1 * R2)/Rs.

We can rewrite this as

Rp * Rs = R1 * R2

Plugging in our numbers (Rp = 6, Rs = 25), we see that R1 + R2 = 150. What two numbers in the vicinity of 12 and 13 have the product of 150 and a sum of 25? Immediately 10 and 15 come to mind! Easy enough!

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How high does a rocket have to go above Earth's surface before its weight is half of what it is on Earth?
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Answer:

h=1.6\times 10^6\ m

Explanation:

As we know that the acceleration due to gravity decreases with height.

At certain height it will get to the half of its value on the surface of the earth.

As we know that the weight on the surface of the earth is given as:

w=m.g

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g = acceleration due to gravity of the substance

Since mass of the substance is constant so the variation is weight is possible only due to change in the acceleration due to gravity.

<u>We know that the variation of the acceleration due gravity with height is given as:</u>

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g = acceleration due to gravity at the earth's surface

h = height of the object

R = radius of the earth = 6400\ km

according to question the weight becomes half, so,:

4.9=9.8\times (1-\frac{2h}{6400\times10^3} )

h=1.6\times 10^6\ m is the height a rocket has to go above Earth's surface before its weight is half of what it is on Earth.

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