Question

You flip a coin straight up if the coin reaches a high point of 0.25 m above where you released it what was the initial speed?

Answer 1

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

$\Rightarrow v^2-u^2=2as$

Putting values

$\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s$

Thus, the initial velocity is 2.21 m/s