Answer:
The pressure is 
The temperature is 
Explanation:
Generally Gibbs free energy is mathematically represented as
Where E is the enthalpy
PV is the pressure volume energy (i.e PV energy)
S is the entropy
T is the temperature
For stability to occur the Gibbs free energy must be equal to zero
Considering Diamond
So at temperature of T = 300 K
making P the subject
Now substituting 300 K for T , 2900 J for E ,
for V and 
for S
The negative sign signifies the direction of the pressure
Given that 
making T the subject
Substituting into the equation
Answer:
C. Heat and Pressure
Explanation:
The arrow which is labeled A points from igneous rock to metamorphic rock.
There are three types of Rocks:
1. Igneous Rock
2. Metamorphic Rock
3. Sedimentary Rock
Rock cycle:
Rock cycle is the process that describes the transition between these three types of rocks. Each type has its own form and its own equilibrium condition. The rock type alters when it is pushed out of its equilibrium conditions.
Transition of Igneous rock to Metamorphic rock:
Igneous rock forms when magma cools down. The transition of Igneous Rock to Metamorphic Rock is a result of a process called Metamorphism. Metamorphism is the alteration in the structure of rock as a result of certain heat and pressure conditions. Inside Earth heat comes from pressure. Heat with pressure does not melt the rock but it bakes the rock. Baking is not melting but it changes the shape of the rock while it is still solid. It actually forms crystals. Because the rock changes its structure, it is called Metamorphic Rock.
Answer:
1.19 m/s²
Explanation:
The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so
f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀ (1)
Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²
Equating (1) and (2) we ave
2(√mg/μ)/f = T²g/4π²
Making g subject of the formula
g = 2π√(2√(m/μ)/f)/T
The period T = 316 s/100 = 3.16 s
Substituting the other values into , we have
g = 2π√(2√(1300 g/1.01 g/m)/200 Hz)/3.16
g = 2π√(2 × 35.877/200 Hz)/3.16
g = 2π√(71.753/200 Hz)/3.16
g = 2π√(0.358)/3.16
g = 2π × 0.599/3.16
g = 1.19 m/s²
Answer:
1.0×10³ N
Explanation:
μs is the static coefficient of friction. That's the friction that acts on a stationary (non-moving) object when being pushed or pulled.
μk is the kinetic coefficient of friction. That's the friction that acts on a moving object.
To budge the pig (while it's still stationary), we need to overcome the static friction.
F = N μs
For a non-moving object on level ground, the normal force N equals the weight.
F = mg μs
Given m = 130 kg and μs = 0.80:
F = (130 kg) (9.8 m/s²) (0.80)
F = 1019.2 N
Rounded to two significant figures, the force needed to budge the pig is 1.0×10³ N.
Scientists need a standard system of measurement to allow for consistency with measurement data (A). Scientists would not be able to understand what other scientists are saying if everyone uses their own system of measurement. Scientists need to take measurements, interpret them and communicate the results to other scientists. That is why a standardized system of taking measurements has been developed. The International System of Units or the Metric system is the measurement system of choice for scientists all over the world today.
