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anyanavicka [17]
3 years ago
10

You flip a coin straight up if the coin reaches a high point of 0.25 m above where you released it what was the initial speed?

Physics
1 answer:
Julli [10]3 years ago
6 0

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

\Rightarrow v^2-u^2=2as\\

Putting values

\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s

Thus, the initial velocity is 2.21 m/s

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