"Acceleration" is the rate at which velocity changes.
So "constant velocity" is a very good definition of "no acceleration".
Choice-B is the correct one.
The solution for this problem is:
v = sqrt(T/µ) where T = m*g = 4*g and µ = 0.0055/2.5 = 0.0022kg/m
Now L = 2 m
For a string the frequencies are n*v/2L
so n*v/2L = 64 and (n+1)*v/2L = 80
Now eqn 2 divided by eqn 1 yields (n + 1)/n = 80/64 = 1.25
=> 1.25 n = n + 1 or .25n = 1 or n = 4
now subbing back into eqn 1 we have 4*v/2L = 64 or v = 32*L = 32*1.9 = 60.8
So 60.8= sqrt(1.1*g/0.0022)
so 1.1*g = 60.8^2*0.0022 = > g = 60.8^2*0.0022/1.1 = 7.39 m/s^2
Answer:
<h2>workdone = force × distance </h2><h2>236J = 18.9cos(o) × 24.4</h2><h2>236/24.4 = 18.9cos(o)</h2><h2>(0.5117)cos^-1 = (o)</h2><h2><u>59.21°</u></h2>
Supermassive black holes astronomers believe to be driving activity in the centers of galaxies.
A galaxy is a device of stars, stellar remnants, interstellar gas, dust, and darkish count, sure together with the aid of gravity. The phrase is derived from the Greek galaxies, actually 'milky', a connection with the Milky manner galaxy that incorporates the solar system. Galaxies, averaging an envisioned a hundred million stars, range in length from dwarfs with much less than one hundred million stars, to the most important galaxies acknowledged – supergiants with one hundred trillion stars, each orbiting its galaxy's center of mass. most of the mass in a typical galaxy is within the form of a darkish count number, with just a few percentages of that mass seen within the form of stars and nebulae. Supermassive black holes are a commonplace feature in the centers of galaxies.
the gap among galaxies is filled with tenuous gasoline (the intergalactic medium) with an average density of much less than one atom consistent with a cubic meter. most galaxies are gravitationally prepared into businesses, clusters, and superclusters. The Milky way is part of the nearby organization, which dominates alongside the Andromeda Galaxy.
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White dwarfs, the energy will all be used and it will begin to shrink.