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aalyn [17]
3 years ago
8

A roller coaster car rapidly picks up speed as it rolls down a slope. as it starts down the slope, its speed is 4 m/s. but 3 sec

onds later, at the bottom of the slope, its speed is 22 m/s. what is its average acceleration?
Physics
1 answer:
Arisa [49]3 years ago
8 0
Vi = 4 m/s
vf = 22 m/s
t = 3s
a = ?

vf = vi + a * t
vf - vi = a * t
a = (vf - vi) / t
a = (22 - 4) / 3
a = 6 m / s^2
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Answer:

Final vertical velocity = -29m/s

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Explanation:

1. The vertical final velocity can be calculated thus: vy = vyo - gt

Where;

vy = vertical velocity (m/s)

vyo = vertical initial velocity (20m/s)

g = acceleration due to gravity (9.8m/s²)

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Hence, vy = vyo - gt

vy = 20 - (9.8 × 5)

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2. x = V0 x t

Where;

x = horizontal distance (m)

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x = 20 × 5

x = 100m

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eimsori [14]

Answer:

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Explanation:

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