<span>The correct expression is
3a^2 + 4b^2
for a = 2 and b = 3
</span> 3*(2)^2 + 4*(3)^2=48
The answer in this case is 48
Answer:0.08
0.0818
Step-by-step explanation:
Answer:
in steps
Step-by-step explanation:
The question did not state if alpha>beta or alpha<beta, so the answer will have 2 answers for each questions
3x²-9x+2=0
x = (-(-9) ± √(-9)²-4*(3)*(2)) / (2*3)
x = (9 + √57) / 6 or x = (9 - √57) / 6 (alpha and beta) or (beta and alpha)
(I) alpha (a) ×beta (b) + alpha² × beta = ab (1+a)
= ((9 + √57) / 6) ((9 - √57) / 6) (1 + (9 ± √57))
= ((9² - (√57)²)/36) (10 ± √57)
= (24/36) (10 ± √57)
= 2/3 (10 ± √57) or (11.7 or 1.63)
(ii) alpha²-alpha×beta+beta² = a² -2ab + b² +ab = (a - b)² + ab
if a is alpha
= ((9 + √57) / 6) - ((9 - √57) / 6)) + ((9 + √57) / 6) ((9 - √57) / 6))
= √57/3 + 2/3
= (√57 + 2) / 3
if a is beta
((9 - √57) / 6) - ((9 + √57) / 6)) + ((9 - √57) / 6) ((9 + √57) / 6))
= - √57/3 + 2/3
= - (√57 + 2) / 3
Answer:
1
Step-by-step explanation:
(2*3-1)-(1+3)
(6-1)-4
5-4
1
If this helps you mark as brainlist
Answer:
{1, 2, 3}, {3, 4, 5}
Step-by-step explanation:
Write expressions for three consecutive integers: n, n + 1, n + 2.
Set up an equation for the verbal description: the product (mulitplication) of the two larger integers (the last two) is one less than 7 times the smallest (the first one).
(n + 1)(n + 2) = 7n - 1
Multiply (FOIL) the left side.
n^2 + 3n + 2 = 7n - 1
Subtract 7n and subtract 1 to make the right side 0.
n^2 - 4n + 3 = 0
Factor.
(n - 1)(n - 3) = 0
Set the two factors equal to 0
n - 1 = 0, n - 3 = 0
Solve for n.
n = 1, n = 3
One set of integers begins with 1, so it's {1, 2, 3}.
The other set begins with 3, so it's {3, 4, 5}
