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Vesnalui [34]
3 years ago
9

State the formula for finding the volume of a cylinder Will give brainlist!!!

Chemistry
2 answers:
uranmaximum [27]3 years ago
5 0
Volume of a cylinder: V= pi (r)^2(h)
ValentinkaMS [17]3 years ago
4 0
Volume of s cylinder= pi r^2 h
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Which statements describe lattice energy?
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Answer:

It is the energy the ions absorb when they form a crystalline compound.


Explanation:

Lattice energy is the energy released upon the formation of a crystal lattice structure.
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Which elements are metals? check all that apply. rhenium (re) boron (b) lithium (li) krypton (kr) phosphorus (p) mercury (hg)?
tangare [24]

Lithium, mercury, and rhenium are all metals.

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Calculate the food energy (joules/
Anna007 [38]

Calculate the food energy (joules/g) of one of your food samples. one chemistry calorie is equal to 4.186 joules. convert the energy you calculated to kilojoules (1 kj = 1000 j). since nothing is given, an example is avocadoes have 160 cal/100 g serving

(160 cal/ 100 g)(4.186 J/ 1 cal) (1 kJ/1000 J) = 0.0067 kJ/g

5 0
3 years ago
a prescriber has ordered childrens motrin 400 mg po q6h for a child who weighs 60 kg. how many mg/kg is the child receiving
DedPeter [7]

Answer:

6.67 mg/kg     per dose   ( 26.67 mg/kg   per day)

Explanation:

400 mg / 60 kg = 6 2/3  mg/kg  per dose

   per <em>DAY</em>  is  four times this number

5 0
2 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
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