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gayaneshka [121]
3 years ago
15

Solve the system by eliminating one of the variables by addition or subtraction

Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Answer:

(2,0)

Step-by-step explanation:

2x-y=4 equation 1

3x+y=6 equation 2

5x=10 eliminate y by adding equations

x=2

solve for y

2x-y=4

2(2)-y=4

4-y=4

-y=0

y=0

check answer:

3x+y=6

3(2)+0=6

6=6

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A group of friends were working on a student film with a budget of $700, which they
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Answer:

76%

Step-by-step explanation:

First do 700 - 168 which is 532

Next we see that 700 is 100% in this scenario

Then we will use the value we seek as ‘x’

So, x% = 532

We can put the two equations, 100%/x% = 700/532

they both have LHS

We can take the inverse from both sides yields

Therefore, the answer is 76%

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3 years ago
What is the quotient of -3/8 and -1/3?
OverLord2011 [107]
(-3/8) / (-1/3)
= (<span>-3/8) x (-3)
= 9/8
= 1 1/8</span>
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3 years ago
Which answer best describes the shape of this distribution?
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4 years ago
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Answer:

B

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3 years ago
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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
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