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tensa zangetsu [6.8K]
3 years ago
6

Hurry need help ASAP

Physics
2 answers:
lina2011 [118]3 years ago
6 0

Answer:

last one

Explanation:

photoshop1234 [79]3 years ago
5 0
A gas and liquid solution.
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A man drops a ball off of a 7.2 m high cliff, what is the ball's velocity as it hits the ground?
QveST [7]

Answer:

19.3 m/s

  1. Explanation:

Take down to be positive.  Given:

Δy = 19 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (19 m)

v = 19.3 m/s

<em>My camera quality is bad. Sorry..</em>

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3 years ago
Energy is transferred by the process of convection from the hot water at the bottom of the tank to the cooler water at the top.
iragen [17]
The transfer of energy means, in convention process, transport of matter. In this case, hot water has lower density than cool water. The water with less density ascends and leaves gaps that are occupied with cooler water "packages".
7 0
3 years ago
How much force will a 5 kg rock hit the Earth with if it falls<br> for 1 second?
Angelina_Jolie [31]

Answer:

f

Explanation:

f

6 0
3 years ago
The drum shown in the figure has a radius of 0.40 m and a moment of inertia of 2.3 kg • m2 about an axis perpendicular to it thr
Citrus2011 [14]

The constant force applied to the rope is 7.72 N.

<h3>Net torque on the drum</h3>

The net torque on the drum is calculated as follows;

Fr - F_fr = I \alpha

Linear speed, v = ωr = 23 x 0.4 = 9.2 m/s

distance traveled = 14 m

<h3>Tangential acceleration</h3>

The acceleration of the drum is calculated as follows;

v² = u² + 2as

v² = 0 + 2as

v² = 2as

a = v²/2s

a = (9.2)/2(14)

a = 0.329 m/s²

<h3>Angular acceleration of the drum</h3>

\alpha = \frac{a}{r} = \frac{0.329}{0.4} = 0.82  \ rad/s^2

<h3>Applied force</h3>

The constant force applied to the rope is calculated as follows;

Fr - F_fr = I \alpha\\\\Fr = I \alpha + F_fr\\\\F = \frac{ I \alpha + F_fr}{r} \\\\F = \frac{2.3(0.82) \ + \ 3(0.4)}{0.4} \\\\F = 7.72 \ N

Learn more about net torque here: brainly.com/question/15262027

7 0
2 years ago
At a certain point in space, there is a potential of 800 V relative to zero. What is the potential energy of the system when a +
sammy [17]

To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

V = \frac{k_e q}{r}

k_e = Coulomb's constant

q = Charge

r = Radius

At the same time

U = \frac{k_e q_1q_2}{r}

The values of variables are the same, then if we replace in a single equation we have this expression,

U  = Vq

If we replace the values, we have finally that the charge is,

V = 800V

q = 1\mu C

U = (800V)(1*10^{-6}C)

U = 8*10^{-4}J

Therefore the potential energy of the system is 8*10^{-4} J

7 0
3 years ago
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