Explanation:
Process A allows the chromosome number in the dog cells to be reduced by half. This is only possible due to meiosis as it undergoes 2 phases of meiosis/cell division which is meiosis I and II. (From 2n to 4n to 2n to n)
(After mitosis, the chromosome number will remain constant even though DNA replication occured in S phase, as there is only 1 phase of mitosis/cell division, so from 2n to 4n back to 2n)
Process B allows the dog gamete cells to undergo fertilization and produce a zygote, therefore the chromosome number returns back to 2n.
(Pollination only occurs in plants, not in animals such as dogs and humans)
The correct answer is Meiosis and Fertilization.
