Explanation:
Equilibrium position in y direction:
W = Fb (Weight of the block is equal to buoyant force)
m*g = V*p*g
V under water = A*h
hence,
m = A*h*p
Using Newton 2nd Law
Hence, T time period
T = 2*pi*sqrt ( h / g )
Answer:
Given that,
- Power = 2000 W
- time = 60 seconds
- distance= 10m
Power = work done ÷ time
Here, since the movement is vertical, w = mgh
So,
Power = mgh÷t
2000 = (m × 9.8 ×10) ÷ 60
m = (2000 ×60) ÷98
m = 1224.5kg
The initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s
<h3>What fraction of the initial mass of the spacecraft?</h3>
Increase the speed: Vf-Vi = 2.2 m/s
Speed of aircraft: Vr = 400 m/s
Speed of ejected products: Vrel = 1000 m/s
The answer is:
So, the initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s
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Answer:
20 mA
Explanation:
We have given that the transformer convert 120 V to 12 V means it is a step down transformer
The turn ratio of the transformer is given as here is primary voltage and is secondary voltage
As the voltage decreases from primary to secondary so current will increase from primary to secondary
We have given output current that is secondary current so primary that is input current will be less
So input current