It would be in the visible light wavelength, specifically in the color green.
Answer: ch4 + 2o2 --> co2 + 2h2o Now let's convert the grams of methane and oxygen to moles and see which one is the limiting reagent. 8 g methane (1 mole/16 g) = 0.5 mole methane
Explanation:
Answer:
2.88 L.
Explanation:
- To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant.
T is the temperature of the gas in K.
- If n and T is constant, and have two different values of (P and V):
<em>P₁V₁ = P₂V₂</em>
<em></em>
P₁ = 1.0 atm, V₁ = 7.2 L.
P₂ = 2.5 atm, V₂ = ??? L.
<em>∴ V₂ = P₁V₁/P₂ </em>= (1.0 atm)(7.2 L)/(2.5 atm) = <em>2.88 L.</em>
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