Question 18 of 32

Where did coper find

ladessa [460]

Answer:

Copper is element number 29

4th row

11th column

6 0

2 years ago

Given below is the balanced equation for the combustion of decane. 2C10H22 (l) + 31O2 (g) --> 20CO2 (g) + 22H2O (g) What is t

Aleks [24]

Answer: The ratio of carbon dioxide molecules to oxygen molecules is 20 :31

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced combustion reaction is,:

$2C_{10}H_{22}(l)+31O_2(g)\rightarrow 20CO_2(g)+22H_2O(g)$

Thus the ratio of carbon dioxide molecules to oxygen molecules is 20 : 31

3 0

3 years ago

Hiii pls help me to write out the ionic equation

emmasim [6.3K]

Answer:

STEP I

This is the balanced equation for the given reaction:-

$2KOH_{(aq)} + H_2SO_4{}_{(aq)} \rightarrow K_2SO_4{}_{(aq)} + 2H_2O_{(l)}$

STEP II

The compounds marked with (aq) are soluble ionic compounds. They must be

broken into their respective ions.

see, in the equation KOH, H2SO4, and K2SO4 are marked with (aq).

On breaking them into their respective ions :-

2KOH -> 2K+ + 2OH-
H2SO4 -> 2H+ + (SO4)2-
K2SO4 -> 2K+ + (SO4)2-

STEP III

Rewriting these in the form of equation

$\underline{\pmb{2K^+} }+ 2OH^- + 2H^+ + \pmb{\underline{{SO_4{}^{2-}}} \: \rightarrow \: \underline{\pmb{2K^+}}} + \underline{\pmb{SO_4{}^{2-}}} + 2H_2O$

STEP IV

Canceling spectator ions, the ions that appear the same on either side of the equation

(note: in the above step the ions in bold have gotten canceled.)

$\boxed{ \mathfrak{ \red{ 2OH^-{}_{(aq)} + 2H^+{(aq.)} \rightarrow H_2O{}_{(l)}}}}$

This is the net ionic equation.

____________________________

$\\$

$\mathfrak{\underline{\green{ Why\: KOH \:has\: been\: taken\: as\: aqueous ?}}}$

KOH has been taken as aqueous because the question informs us that we have a solution of KOH. by solution it means that KOH has been dissolved in water before use.

[Alkali metal hydroxides are the only halides soluble in water ]

4 0

3 years ago

Write the net ionic equation for the equilibrium that is established when potassium hypochlorite is dissolved in water.

oee [108]

Potassium hypochlorite when dissolved in water would dissociate into ions namely the potassium ions and the hypochlorite ions. Furthermore, hypochlorite ions would interact with water molecules and would decompose further. The dissociation reactions are as follows:

KClO <=> K+ + ClO-
ClO- + H2O <=> HOCl + OH-

Adding the two reactions, would give

KClO + ClO- + H2O = K+ + HOCl + OH- + ClO-

The two ClO- ions in both sides would cancel giving us the net ionic equation:

KClO + H2O = K+ + HOCl + OH-

5 0

3 years ago

if multicellular organism came from unicellular organisms, then are all species ralated, why do you think so?

Alenkinab [10]

Answer:

Explanation:

Most people when asked, “What is the equation of a line?”, will answer, “y = mx + b”. This is the

equation of a line in what is called slope-intercept form where “m” is the slope and “b” is the yintercept. So, how do you find the equation of a line? There are several different ways that you can find

the equation of a line. I find the equation of a line everytime by following the same three steps:

Step 1: Find the slope of the line.

Step 2: Use the slope to find the y-intercept.

Step 3: Use steps 1 and 2 to write the answer.

I will explain these steps by looking a several examples. Please understand that there are often several

different ways to complete each math problem, but I have found through the years that students are most

successful when the do problems the same way each and every time they attempt the problem. If you

know a different way to find the answer that is great, but I am going to show how to do the problem one

way and use the same technique everytime I see this problem.

3 0

3 years ago