I believe it’s A. I know for sure it isn’t D.
Answer:
The minimum stopping distance when the car is moving at
29.0 m/sec = 285.94 m
Explanation:
We know by equation of motion that,
Where, v= final velocity m/sec
u=initial velocity m/sec
a=Acceleration m/
s= Distance traveled before stop m
Case 1
u= 13 m/sec, v=0, s= 57.46 m, a=?
a = -1.47 m/ (a is negative since final velocity is less then initial velocity)
Case 2
u=29 m/sec, v=0, s= ?, a=-1.47 m/ (since same friction force is applied)
s = 285.94 m
Hence the minimum stopping distance when the car is moving at
29.0 m/sec = 285.94 m
1. <span>Molecules rearrange and form new molecules - exchange (they exchange some material in order to produce new things)
2. </span><span>simultaneous decomposition and synthesis - reversible (it can go back)
3. </span><span>bonds broken and elements released - decomposition
4. </span><span>molecules formed from components - synthesis (these components merge and create molecules)</span>
Explanation:
the acceleration will be unchanged according to newton second law of motion
multiply the six sides of the cube(LB), since length is 2000, then breadth will be 2000 also
