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3 years ago

Lila is using a Bunsen burner. She has all of her chemicals on her workstation. Which would be the best lab practice?

2 answers:

8 0

<span>
putting the burner on a stand to keep it away from chemicals
</span>Lila is using a Bunsen burner. She has all of her chemicals on her workstation. Which would be the best<span> lab practice?
</span>

Semmy [17]3 years ago

7 0

Answer:

a, putting the burner on a stand to keep it away from chemicals.

Explanation:

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What is an ore?

iogann1982 [59]

Answer : a rock that contains a metal resource

Reason :

Ore - a naturally occurring solid material from which a metal or valuable mineral can be profitably extracted.

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3 years ago

What happens to a wave if its frequency decreases?

iragen [17]

Answer:hen frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

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3 years ago

A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 6.0 m, y = 10.0 m, and has vel

mihalych1998 [28]

Explanation:

Given that,

Position of the particle at t = 0,

$y=(6i+10j)\ m$

Velocity of the particle at t = 0

$u=(1i+6j)\ m$

Acceleration of the particle,

$a=(5i+7j)\ m/s^2$

Solution,

(a) Let v is the velocity at t = 10 s. Using the equation of kinematics as :

$v=u+at$

$v=(1i+6j)+(5i+7j)10$

$v=(51i+76j)\ m/s$

(b) Let y' is the position at t = 1 s. Again using second equation of kinematics as :

$y'=y+ut+\dfrac{1}{2}at^2$

$y'=(6i+10j)+(1i+6j)1+\dfrac{1}{2}\times (5i+7j)1^2$

$y'=\dfrac{19}{2}i+\dfrac{39}{2}j$

(c) Magnitude of y',

$|y'|=\sqrt{(\dfrac{19}{2})^2+(\dfrac{39}{2})^2}$

|y'| = 21.69 meters

Direction of the y',

$tan\theta=\dfrac{y}{x}$

$tan\theta=\dfrac{39/2}{19/2}$

$\theta=64.02^{\circ}$

Hence, this is the required solution.

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3 years ago

This equation goes with which law?

Alchen [17]

Answer:

I think that's Newton's second law of motion

Explanation:

f = m(v-u)

________

since a = (v-u)t

f = ma

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3 years ago

A dwarf planet discovered out beyond the orbit of Pluto is known to have an orbital period of 619.36 years. What is its average

Maksim231197 [3]

Answer: $72.66 AU=1.089(10)^{10} km$

Explanation:

Let's begin by explaining that according to Kepler’s Third Law of Planetary motion “The square of the orbital period $T$ of a planet is proportional to the cube of the semi-major axis $a$ of its orbit”:

$T^{2}\propto a^{3}$ (1)

Now, if $T$ is measured in years (Earth years), and $a$ is measured in astronomical units (equivalent to the distance between the Sun and the Earth: $1AU=1.5(10)^{8}km$ ), equation (1) becomes: