Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg
I think it would be Kriptonite
Answer:
a mixture of molecules - Box f
atoms of a pure elementa metal - Box D
a solid compound - Box C
a mixture of elements - Box A
Explanation:
Box a has mixture of elements which forms a solid like shape but there are different elements present in the box. The box f has mixture of molecules in which many atoms are combined together. Box c has solid compound with single element.
Answer:
10043.225 J
Explanation:
We'll begin by calculating the amount of heat needed to change ice to water since water at 0°C is ice. This is illustrated below:
Mass (m) = 15.5g
Latent heat of fussion of water (L) = 334J/g
Heat (Q1) =..?
Q1 = mL
Q1 = 15.5 x 334
Q1 = 5177 J
Next, we shall calculate the amount of heat needed to raise the temperature of water from 0°C to 75°C.
This is illustrated below:
Mass = 15.5g
Initial temperature (T1) = 0°C
Final temperature (T2) = 75°C
Change in temperature (ΔT) = T2 – T1 = 75 – 0 = 75°C
Specific heat capacity (C) of water = 4.186J/g°C
Heat (Q2) =?
Q2 = MCΔT
Q2 = 15.5 x 4.186 x 75
Q2 = 4866.225 J
The overall heat energy needed is given by:
QT = Q1 + Q2
QT = 5177 + 4866.225
QT = 10043.225 J
Therefore, the amount of energy required is 10043.225 J
