Answer:
99% Confidence interval: (1196,1973)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 20
Mean, μ = 1584
Standard Deviation, σ = 607
99% Confidence interval:
Putting the values, we get,
Thus, there is a 99% chance that it will break in approximately 1196 to 1972
Since , by the remainder theorem this means that <em>x</em> - 6 divides <em>f(x)</em> exactly. This means there are constants <em>a</em>, <em>b</em>, and <em>c</em> such that
Multiplying both sides by <em>x</em> - 6 gives
Then <em>a</em>, <em>b</em>, <em>c</em> satisfy
and solving this system gives <em>a</em> = 2, <em>b</em> = -7, and <em>c</em> = 3.
So, we have
The quadratic term can be factored as
which leaves us with
so that the zeros of <em>f(x)</em> are 6, 1/2, and 3.
