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topjm [15]
3 years ago
10

Does the system have a no solution or infinitely many solutions Y=2/3x+2-2x+3y=6

Mathematics
2 answers:
oee [108]3 years ago
8 0

Answer:

answer for y=2/3x+2: y=2/3x+2

answer for -2x+3y=6: x=3/2y-3

pls give brainliest

KatRina [158]3 years ago
4 0

Answer:

There are infinitely many solutions.

Step-by-step explanation:

There are infinitely many solutions because if you solve the equations, you will find that both of the equations are actually the same, so there is infinitely many solutions.

Showing that both equations are equal:  y=2/3x+2       -2x+3y=6

y=2/3x+2  Multiply by 3 on both sides

3y=2x+6 Rearrange (-2x on both sides)

3y-2x=6 More rearrangement

-2x+3y=6 Now, if you look back at the second equation, you will see that they are both the same.

                     

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Try this option:
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3. example:
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ludmilkaskok [199]

Answer:

\dfrac{dy}{dx}=- \dfrac{1}{\left(x - 1\right) \left(x + 1\right)}

Step-by-step explanation:

Given:

y = \ln{\left(\dfrac{x + 1}{x - 1}\right)^{\frac{1}{2}}

using the properties of log we can take the power 1/2 and multiply it.

y = \dfrac{1}{2}\ln{\left(\dfrac{x + 1}{x - 1}\right)

now we can differentiate:

\dfrac{dy}{dx} = \dfrac{1}{2}\dfrac{1}{\left(\dfrac{x + 1}{x - 1}\right)}\left(\dfrac{d}{dx}\left(\dfrac{x+1}{x-1}\right)\right)

\dfrac{dy}{dx} = \dfrac{1}{2}\left(\dfrac{x - 1}{x + 1}\right)\left(- \dfrac{2}{\left(x - 1\right)^{2}}\right)

\dfrac{dy}{dx}=- \dfrac{1}{\left(x - 1\right) \left(x + 1\right)}

this is our answer!

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