1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
topjm [15]
3 years ago
10

Does the system have a no solution or infinitely many solutions Y=2/3x+2-2x+3y=6

Mathematics
2 answers:
oee [108]3 years ago
8 0

Answer:

answer for y=2/3x+2: y=2/3x+2

answer for -2x+3y=6: x=3/2y-3

pls give brainliest

KatRina [158]3 years ago
4 0

Answer:

There are infinitely many solutions.

Step-by-step explanation:

There are infinitely many solutions because if you solve the equations, you will find that both of the equations are actually the same, so there is infinitely many solutions.

Showing that both equations are equal:  y=2/3x+2       -2x+3y=6

y=2/3x+2  Multiply by 3 on both sides

3y=2x+6 Rearrange (-2x on both sides)

3y-2x=6 More rearrangement

-2x+3y=6 Now, if you look back at the second equation, you will see that they are both the same.

                     

You might be interested in
Evaluate the expression for the given values.
elixir [45]

Answer:

3

Step-by-step explanation:

1•5-2

5-2=3

8 0
3 years ago
Read 2 more answers
Mary has $267 in her checking account . She writes checks for $33,$65 and 112. What is the balance in her account now ?
natulia [17]

Answer:

57

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the value of x? 6x−2(x 4)=12
jonny [76]

Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored

<span>Equation at the end of step  2  :</span>  6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0 </span><span>Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 6x2-x-4</span> 

The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span> 

Step-2 : Find two factors of  -24  whose sum equals the coefficient of the middle term, which is  <span> -1 </span>.

<span><span>     -24   +   1   =   -23</span><span>     -12   +   2   =   -10</span><span>     -8   +   3   =   -5</span><span>     -6   +   4   =   -2</span><span>     -4   +   6   =   2</span><span>     -3   +   8   =   5</span><span>     -2   +   12   =   10</span><span>     -1   +   24   =   23
</span></span>

Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored

<span>Equation at the end of step  2  :</span><span> 6x2 - x - 4 = 0 </span>

3 0
3 years ago
Evaluate.
Temka [501]

9514 1404 393

Answer:

  -7/48

Step-by-step explanation:

Put the numbers in place of the corresponding variables and do the arithmetic.

  \dfrac{-\left|1\dfrac{7}{8}+(-1)\right|}{2-(-4)}=\dfrac{-\dfrac{7}{8}}{6}=-\dfrac{7}{8\cdot6}=\boxed{-\dfrac{7}{48}}

8 0
3 years ago
Find the length of the missing side of the right triangle given the area of the two triangles find the length of the sides of th
irina [24]
From here, it looks like all three sides of the right triangle are missing. I don't see any of them in the question.
3 0
3 years ago
Other questions:
  • Y+ 1/2 =-3/4 How would you do this one
    11·2 answers
  • What is the value of t?
    14·1 answer
  • Evaluate (2x^2+y^2)3
    11·2 answers
  • Ten times the sum of half a number and 6 is 8
    13·1 answer
  • Please help on this 2 questions I have
    9·1 answer
  • Please answer this question now
    14·1 answer
  • Please help me with integers! Thank you!
    14·1 answer
  • How are the expressions "1/4 of 12" and "12divided by 4" related
    15·2 answers
  • Factor: 2x^2 + 5x + 3​
    9·1 answer
  • !!!20 POINTS!!!
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!