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Dmitry [639]
2 years ago
10

15 7/8 - 5 3/4

Mathematics
1 answer:
dem82 [27]2 years ago
8 0
First, set ur denominator to lcm which is 8

15 7/8-5 6/8

= 10 1/8
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What number is halfway between -15 and 20
ollegr [7]

Answer : 2.5

Solution:

To find the halfway number it means that you need to find the middle most value using the formula

Mid value = (X + Y) / 2

So in this case it would be,

Mid value =  (-15 + 20 ) / 2

Mid Value = ( 5 ) / 2

Mid Value = 2.5 answer

Hope this helps in understanding the question! :)

Note : do not forget the negative sign as it will change the answer and may cost you marks!

4 0
2 years ago
What is the median of data set 32 25 25 32 32 10 -10 25 ​
LuckyWell [14K]

Answer:

-10, 10, 25, 25, 25, 32, 32, 32

Its 25

Step-by-step explanation:

The median is the middle number if there are an even amount of numbers you would have two medians add them the divide by two

4 0
2 years ago
Read 2 more answers
Cans someone pls give me the answer to this?
romanna [79]

Answer:the value drops 100$ every 3 years

Step-by-step explanation:

moves down 100 every three years

8 0
2 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
Read 2 more answers
Factor 9x^2+66xy+121y^2
Korvikt [17]
Answer: (3x + 11y)^2

Demonstration:

The polynomial is a perfect square trinomial, because:

1) √ [9x^2] = 3x

2) √121y^2] = 11y

3) 66xy = 2 *(3x)(11y)

Then it is factored as a square binomial, being the factored expression:

 [ 3x + 11y]^2

Now you can verify working backwar, i.e expanding the parenthesis.

Remember that the expansion of a square binomial is:

- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2

=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.

7 0
3 years ago
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