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Dmitry [639]
3 years ago
10

15 7/8 - 5 3/4

Mathematics
1 answer:
dem82 [27]3 years ago
8 0
First, set ur denominator to lcm which is 8

15 7/8-5 6/8

= 10 1/8
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(3+62) x (25-17) + 3*2 <br> 2 is an exponent btw
MAXImum [283]

Answer:

529

Step-by-step explanation:

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4 years ago
How do you increase 429 Grams by 31%
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If you want to increase something by 31% then...

100%+31%=131% or 1.31

you multiply it by 131% or 1.31. So for 429 grams...

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3 years ago
What is -6x plus 18 equals -6
Neporo4naja [7]
It’s going to be -18

First add 6 to both sides to get x by itself

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7 0
3 years ago
A researcher compares differences in positivity between participants in a low-, middle-, or upper-middle-class family. If she ob
777dan777 [17]

Answer:

(2, 12)

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have 3 groups and on each group from j=1,\dots,n_j we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

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SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1=3-1=2 where k =3 represent the number of groups.  

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3 0
3 years ago
Best of three In a best out of three series played between teams A and B, the team that gets two wins first wins the entire seri
konstantin123 [22]

Answer:

a) P (x = 2 games )  =  0.49 + 0.09 = 0.58

    P ( x = 3 games ) = 0.063 + 0.147 + 0.147 + 0.063 = 0.42

b) = 2.42 ≈ 2 games

c) P (x = 2 games )  =  0.49 + 0.09 = 0.58

Step-by-step explanation:

Team A chance of winning a game in the series. P( team A ) = 70% = 0.7

P ( team B ) = 0.3

probability of series ending after two games = 58% = 0.58

<u>A) Determine the probability distribution of X number of games played in the series</u>

First we have to consider the possible combinations that will decide the series and they are

( A,A ) , ( B,B) , ( A,B,B) , ( A,B,A ) , ( B,A,A ), ( B,A,B)  = 6 Combinations

( A,A ) = 0.7 * 0.7 = 0.49

( B,B ) = 0.3 * 0.3 = 0.09

( A,B,B ) = 0.7 * 0.3 *0.3 = 0.063

( A,B,A ) = 0.147

( B,A,A ) = 0.147

( B,A,B ) = 0.063

The distribution of the games in the series can be either game or three games before the end of the series

P (x = 2 games )  =  0.49 + 0.09 = 0.58

P ( x = 3 games ) = 0.063 + 0.147 + 0.147 + 0.063 = 0.42

<u>B) the expected number of games to be played </u>

∑ x(Px) = ( 2 * 0.58 ) + 3 ( 0.42 ) = 2.42 ≈ 2 games

<u>C)  Verify that the probability that series ends after two games = 58%</u>

sample space of all possible sequences of wins and losses

( A,A ) , ( B,B) , ( A,B,B) , ( A,B,A ) , ( B,A,A ), ( B,A,B)  = 6 Combinations

( A,A ) = 0.7 * 0.7 = 0.49

( B,B ) = 0.3 * 0.3 = 0.09

( A,B,B ) = 0.7 * 0.3 *0.3 = 0.063

( A,B,A ) = 0.147

( B,A,A ) = 0.147

( B,A,B ) = 0.063

hence :

P (x = 2 games )  =  0.49 + 0.09 = 0.58

6 0
3 years ago
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