Whether an element is classified as a major or as a trace mineral is determined by

2 answers:

5 0

Whether an element is classified as a major or as a trace mineral is determined by "<span>the amounts daily required by the body".

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Calcium, magnesium, phosphorus, potassium, chloride and sulfur are all examples of the major minerals and these are the minerals a body needs in large quantity as opposed to include iron, copper, zinc, manganese, fluoride, selenium and cobalt, which are all trace minerals and are needed in very little quantity.

Svetllana [295]2 years ago

4 0

<h2>Element Trace Mineral is Determination</h2>

Whether an element is classified as a major or as a trace mineral is determined by the amounts needed daily by the body. Species need minerals in varying amounts, but commonly required plant trace elements such as copper (Cu), Boron (B), Zinc (Zn), Manganese (Mn) and Molybdenum (Mo).

Animals require Manganese (Mn), iodine (I) and cobalt (Co). Human requires trace minerals in small amounts such as iron (Fe), iodine (I), fluoride (F), copper (Cu), Zinc (Zn), Chromium (Cr), Selenium (Se), Manganese (Mn) and Molybdenum (Mo).

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Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a

slega [8]

Answer:

$\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

$\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}$

From Equation (2), the molar ratio of iodine to thiosulfate is

$\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}$

Combining the two ratios, we get

$\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}$