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DiKsa [7]
2 years ago
15

Different between an architect and an engineer​

Engineering
1 answer:
Bezzdna [24]2 years ago
3 0

different between an architect and an engineer

Civil engineers work on the construction of the building. ... In short it can be said that while an Architect is a building designer, a Civil Engineer is a structural expert, who in

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(E. Call the hospital to take them away
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3 years ago
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Georgia Tech is committed to creating solutions to some of the world’s most pressing challenges. Tell us how you have improved o
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Georgia Tech is committed to WGAR 53566 THE ANSWER IS JELLY IS KING AND THE JELLY IS KING AND  hope to improve the human condition in your community.

Explanation:

6 0
3 years ago
Calculate the load, PP, that would cause AA to be displaced 0.01 inches to the right. The wires ABAB and ACAC are A36 steel and
Nataly [62]

Answer:

P = 4.745 kips

Explanation:

Given

ΔL = 0.01 in

E = 29000 KSI

D = 1/2 in  

LAB = LAC = L = 12 in

We get the area as follows

A = π*D²/4 = π*(1/2 in)²/4 = (π/16) in²

Then we use the formula

ΔL = P*L/(A*E)

For AB:

ΔL(AB) = PAB*L/(A*E) = PAB*12 in/((π/16) in²*29*10⁶ PSI)

⇒  ΔL(AB) = (2.107*10⁻⁶ in/lbf)*PAB

For AC:

ΔL(AC) = PAC*L/(A*E) = PAC*12 in/((π/16) in²*29*10⁶ PSI)

⇒  ΔL(AC) = (2.107*10⁻⁶ in/lbf)*PAC

Now, we use the condition

ΔL = ΔL(AB)ₓ + ΔL(AC)ₓ = ΔL(AB)*Cos 30° + ΔL(AC)*Cos 30° = 0.01 in

⇒  ΔL = (2.107*10⁻⁶ in/lbf)*PAB*Cos 30°+(2.107*10⁻⁶ in/lbf)*PAC*Cos 30°= 0.01 in

Knowing that   PAB*Cos 30°+PAC*Cos 30° = P

we have

(2.107*10⁻⁶ in/lbf)*P = 0.01 in

⇒  P = 4745.11 lb = 4.745 kips

The pic shown can help to understand the question.

5 0
3 years ago
Mark each one as either Potential or Kinetic Energy?
never [62]
A- kinety
b- potential
3 0
2 years ago
Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.
Eva8 [605]

Correct answer is option E. No dimensions

As we know formula Pressure (P) is \frac{F}{A}

also,

  • Dimensional formula of <em>Pressure is </em>M^{1}L^{-1}T^{-2}
  • Dimensional formula of <em>length is L </em>
  • Dimensional formula of <em>mass is M</em>
  • Dimensional formula  of <em>velocity is </em>L^{1} T^{-1}

So, as given W=\frac{P*L^{3} }{M*V^{2} }

Dimensional formula of W =\frac{M^{1}L^{-1}T^{-2}  L^{3}  }{M^{1} L^{2}T^{-2}   }

since all terms get cancelled

Work is dimensionless i.e no dimensions

Learn more about dimensions here brainly.com/question/20351712

#SPJ10

6 0
2 years ago
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