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kolbaska11 [484]
3 years ago
6

A column has a 4.8 cm by 8.7 cm rectangular cross section and a height 4 mm . The column is fixed at both ends and has a lateral

support at mid-height for the weak axis. The material has E = 200 GPa and σY = 250 MPa.a. The factor of safety for the column yielding is FS 1.5. What is the maximum load that can be applied based on the column yielding due to the normal stress? Assume the load is applied at the centroid of the section. Express your answer with appropriate units to three significant figures. b. The design is to have a factor of safety for buckling FS 2.5. What is the maximum load based on buckling in the strong axis of the column? Express your answer with appropriate units to three significant figures.
Engineering
1 answer:
Elden [556K]3 years ago
3 0
I’m literally so sorry
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Answer:

False

Explanation:

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3 0
3 years ago
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Write the following decorators and apply them to a single function (applying multiple decorators to a single function): 1. The f
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Answer:

Complete question is:

write the following decorators and apply them to a single function (applying multiple decorators to a single function):

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2. The decorator will return the wrapper per usual.

3. The second decorator is called emphasis and has an inner function called wrapper. The purpose of this decorator is to add the html tags of <em> and </em> to the argument of the decorator similar to step 1. The return value of the wrapper should look like: return “<em>” + func() + “</em>.

4. Use the greetings() function in problem 1 as the decorated function that simply prints “Hello”.

5. Apply both decorators (by @ operator to greetings()).

6. Invoke the greetings() function and capture the result.

Code :

def strong_decorator(func):

def func_wrapper(name):

return "<strong>{0}</strong>".format(func(name))

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def func_wrapper(name):

return "<em>{0}</em>".format(func(name))

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@em_decorator

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Explanation:

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I hope this help you!
8 0
1 year ago
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Answer:

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