The equation that is equivalent to S=pi r^2 h is h = S/pir^2
<h3>Subject of formula</h3>
This is a way of representing a variable with another. Given the equation
S=pi r^2 h
We are to make 'h" the subject of the formula.
Divide both sides by pir^2
S/pir^2 =pi r^2 h/pir^2
h = S/pir^2
Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2
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Answer:
(11,-28)
Step-by-step explanation:
Well first turn 1/7 and 1/5 into decimals which would be .142857 and .2 Add those to 7 and 5 to get 7.143 (I rounded this to the nearest thousandth) and 5.2 Divide those and you get 1.374
Answer:
Step-by-step explanation:
u put the gs with each other by flipping the one that was changed
3.6g-1.6g=8-2
2g=6
g=6/2
g=3
Answer:
Step-by-step explanation:
Formula to determine the scale factor,
Scale factor = ![\frac{\text{Dimension of the image}}{\text{Dimension of the original}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BDimension%20of%20the%20image%7D%7D%7B%5Ctext%7BDimension%20of%20the%20original%7D%7D)
2 = ![\frac{P'Q'}{PQ}](https://tex.z-dn.net/?f=%5Cfrac%7BP%27Q%27%7D%7BPQ%7D)
2 = ![\frac{P'Q'}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BP%27Q%27%7D%7B2%7D)
P'Q' = 4 cm
Similarly, for the length of A'B',
2 = ![\frac{A'B'}{AB}](https://tex.z-dn.net/?f=%5Cfrac%7BA%27B%27%7D%7BAB%7D)
2 = ![\frac{A'B'}{1.5}](https://tex.z-dn.net/?f=%5Cfrac%7BA%27B%27%7D%7B1.5%7D)
A'B' = 3 cm
For the length of M'N',
2 = ![\frac{M'N'}{MN}](https://tex.z-dn.net/?f=%5Cfrac%7BM%27N%27%7D%7BMN%7D)
2 = ![\frac{M'N'}{3}](https://tex.z-dn.net/?f=%5Cfrac%7BM%27N%27%7D%7B3%7D)
M'N' = 6 cm