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zvonat [6]
4 years ago
12

If a capacitor has opposite 4.9 μc charges on the plates, and an electric field of 1.6 kv/mm is desired between the plates, what

must each plate's area be?
Physics
1 answer:
Temka [501]4 years ago
3 0
Q = 4.6E-6 C 
<span>E = 2.6 kV/mm = 2600 kV/m = 2600000 V/m </span>
<span>ε = 8.85E-12 F/m </span>
<span>E = Q/Aε </span>
<span>A = Q/Eε = 4.6E-6/(2600000*8.85E-12) = 0.2 m^2</span>
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