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tino4ka555 [31]
3 years ago
6

A ball is projected at an angle of 53º. If the initial velocity is 48 meters/second, what is the vertical component of the veloc

ity with which it was
launched?
OA. 31 meters/second
OB. 38 meters/second
OC
44 meters/second
OD
55 meters/second
Physics
1 answer:
solong [7]3 years ago
5 0

Answer: B

Explanation:

The vertical component of a vector such as velocity is the magnitude of the vector multiplied by the sine of the angle.

V_y=48*sin(53)=38.3m/s

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Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is
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Explanation:

Relation between potential energy and charge is as follows.

           U = qV

or,    \Delta U = q \times \Delta V

                   = 1.6 \times 10^{-19} \times 70 \times 10^{-3}

                   = 112 \times 10^{-22} J

or,                = 1.12 \times 10^{20} J

Therefore, we can conclude that change in the electrical potential energy \Delta U is 1.12 \times 10^{20} J.

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3 years ago
Given uranium 235 go through an alpha, beta, beta, alpha, gamma, neutron and alpha. What do you have now?
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Answer:

b. 88, 222

Explanation:

235U₉₂ ----→ Alpha --------→  231P₉₀  ----→- beta -----→ 231Q₉₁ ------→-beta -------→231R₉₂--------→-alpha ------→-227S₉₀ ------→ gamma -----→-227S₉₀ ----------→ neutron ------→-226T₉₀-----------→ alpha --------→222 X ₈₈

Atomic No is 88 , atomic weight = 222 .

3 0
3 years ago
If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st
liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0
3 years ago
Compare and contrast the life cycle of a low mass star and a high mass star
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A 142 kg boulder is located near the edge of a cliff 25 m above the ground. What is the gravitational potential energy of the bo
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PE = 142 * 25 * 9.81
PE = 34825.5 J
8 0
3 years ago
Read 2 more answers
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