A ball is projected at an angle of 53º. If the initial velocity is 48 meters/second, what is the vertical component of the veloc
1 answer:
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Answer:
Maximum height, h = 11.32 meters
Explanation:
It is given that,
The baseball is thrown directly upward at time, t = 0
Initial speed of the baseball, u = 14.9 m/s
Ignoring the resistance in this case and using a = g = 9.8 m/s²
We have to find the maximum height the ball reaches above where it leaves your hand. Let the maximum height is h. Using third equation of motion as :
At maximum height, v = 0
and a = -g = -9.8 m/s²
h = 11.32 meters
Hence, the maximum height of the baseball is 11.32 meters.
Answer:
Internal resistance = 0.545 ohm
Explanation:
As per ohm's law we know that
here we know that
i = electric current = 2.75 A
V = potential difference = 1.50 Volts
now from above equation we have
now we have