1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanzania [10]
3 years ago
10

The Canby’s dropwort grows in wetlands in Georgia. It is an endangered plant because wetlands have been cleared for agriculture

and construction. The larvae of the black swallowtail butterfly eat this plant.
What would MOST LIKELY happen to the black swallowtail butterfly if these plants continue to decrease?
A) The number of butterflies will drop.
B) The number of larvae will not change.
Eliminate
C) The larvae will find other plants to eat.
D) The butterflies will lay their eggs on other plants.
Chemistry
2 answers:
torisob [31]3 years ago
8 0
A) The number of butterflies will drop.
Nataly_w [17]3 years ago
5 0

Answer: Option A

Explanation: The number of butterflies will drop, as the larvae of swallowtail butterfly eat this plant. The plant will decrease in huge amount.

One because of habitat loss as the the wetlands in Georgia have been cleared due to agriculture and construction.

Secondly, the endangered plant is being eaten by the larvae so there will be a decrease in the population of the plant.

The number of butterflies will drop because the plant population will decrease.

You might be interested in
Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He. W
Marat540 [252]

Answer :

The total pressure inside the cylinder is, 6.7 atm

The mole fraction of N_2 in the mixture is, 0.52

Solution :

First we have to calculate the total pressure inside the cylinder.

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

P_T=p_{N_2}+p_{O_2}+p_{Ar}+p_{He}

Now put all the given values is expression, we get the total pressure inside the cylinder.

P_T=3.5+2.8+0.25+0.15=6.7atm

Now we have to calculate the mole fraction of N_2 in the mixture.

Formula used :

p_{N_2}=X_{N_2}\times P_T

where,

P_T = total pressure = 6.7 atm

p_{N_2} = partial pressure of nitrogen gas = 3.5 atm

X_{N_2} = mole fraction of nitrogen gas = ?

Now put all the given values in the above formula, we get

3.5atm=X_{N_2}\times 6.7atm

X_{N_2}=0.52

Therefore, the total pressure inside the cylinder is, 6.7 atm and the mole fraction of N_2 in the mixture is, 0.52

6 0
3 years ago
Help please .......<br><br>​
pshichka [43]

Answer:

The first one is a divergent plate boundary.

The second is a convergent plate boundary.

The third is a transform plate boundary.

Explanation:

8 0
3 years ago
The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
3 years ago
At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil
Romashka [77]

Answer:

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 52 kPa

V_1 = initial volume of gas = 2.0m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 21.1^oC=273+21.1=294.1K

T_2 = final temperature of gas = -5.0^oC=273+(-5.0)=268 K

Now put all the given values in the above equation, we get:

\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

3 0
3 years ago
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0
2 years ago
Other questions:
  • Which best describes the relationships between subatomic particles in any neutral atom? * 1 point the number of electrons equals
    5·1 answer
  • How many moles of cei3 are in 9.42 × 1021 formula units of cei3 (cerium(iii) iodide; a bright, water, soluble solid). answer in
    11·1 answer
  • Any form of matter that is uniform throughout and has consistent properties
    6·1 answer
  • A company issued 6%, 15-year bonds with a face amount of $67 million. The market yield for bonds of similar risk and maturity is
    6·1 answer
  • The tilt of the Earth on its axis does not change? <br> Agree or Disagree?
    9·1 answer
  • Kepler proposed the modern model of the solar system.
    7·2 answers
  • Why do you think we have different seasons?
    15·1 answer
  • PLS PLS PLS PLS HELP IM STRUGGLING
    15·1 answer
  • Explain by means of why is reddish orange is observed when you add sodium chloride
    8·1 answer
  • This is my question in imageIf 16.0 grams of aluminum oxide were actually produced, what is the percent yield of the reaction be
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!